42.0 mL of 0.170 M NaOH and 37.6 mL of 0.420 M NaOH. Assume that the volumes are additive. Enter your answers, separated by a comma, using three significant figures. ΕΙ ΑΣΦ MNa+, MOH = S M
42.0 mL of 0.170 M NaOH and 37.6 mL of 0.420 M NaOH. Assume that the volumes are additive. Enter your answers, separated by a comma, using three significant figures. ΕΙ ΑΣΦ MNa+, MOH = S M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
42.0 mL of 0.170 M NaOH and 37.6 mL of 0.420 M NaOH. Assume that the volumes are additive.
**Task:**
Enter your answers, separated by a comma, using three significant figures.
**Input Box:**
\[ M_{\text{Na}^{+}}, M_{\text{OH}^{-}} = \]
### Explanation:
This problem requires calculating the concentrations of sodium ions (\( \text{Na}^+ \)) and hydroxide ions (\( \text{OH}^- \)) after mixing two solutions of sodium hydroxide (NaOH) with different concentrations. The volumes of the two solutions are additive, meaning they combine to form a single solution without any volume lost.
### Steps to Solve:
1. **Calculate Moles for Each Solution:**
- **Solution 1:** \( 42.0 \, \text{mL} \times 0.170 \, \text{M} \)
- **Solution 2:** \( 37.6 \, \text{mL} \times 0.420 \, \text{M} \)
2. **Find Total Volume:**
- Add the two volumes: \( 42.0 \, \text{mL} + 37.6 \, \text{mL} = 79.6 \, \text{mL} \)
3. **Determine Total Moles of Each Ion:**
- Sodium ions (\( \text{Na}^+ \)) and hydroxide ions (\( \text{OH}^- \)) are in a 1:1 ratio with NaOH, so total moles of \(\text{NaOH}\) are shared equally between \(\text{Na}^+\) and \(\text{OH}^-\).
4. **Calculate New Concentrations:**
- Use the total moles and total volume in liters to find the molarity of each ion in the combined solution.
This calculation involves basic chemistry concepts like concentrations, moles, and solution mixing, and is often used to teach the principles of solution preparation and dilution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b0e7686-0c0d-4eba-ac81-54e736b47f2f%2F745a573c-2386-41f1-b3c7-181eef2240ea%2Fviy6vy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
42.0 mL of 0.170 M NaOH and 37.6 mL of 0.420 M NaOH. Assume that the volumes are additive.
**Task:**
Enter your answers, separated by a comma, using three significant figures.
**Input Box:**
\[ M_{\text{Na}^{+}}, M_{\text{OH}^{-}} = \]
### Explanation:
This problem requires calculating the concentrations of sodium ions (\( \text{Na}^+ \)) and hydroxide ions (\( \text{OH}^- \)) after mixing two solutions of sodium hydroxide (NaOH) with different concentrations. The volumes of the two solutions are additive, meaning they combine to form a single solution without any volume lost.
### Steps to Solve:
1. **Calculate Moles for Each Solution:**
- **Solution 1:** \( 42.0 \, \text{mL} \times 0.170 \, \text{M} \)
- **Solution 2:** \( 37.6 \, \text{mL} \times 0.420 \, \text{M} \)
2. **Find Total Volume:**
- Add the two volumes: \( 42.0 \, \text{mL} + 37.6 \, \text{mL} = 79.6 \, \text{mL} \)
3. **Determine Total Moles of Each Ion:**
- Sodium ions (\( \text{Na}^+ \)) and hydroxide ions (\( \text{OH}^- \)) are in a 1:1 ratio with NaOH, so total moles of \(\text{NaOH}\) are shared equally between \(\text{Na}^+\) and \(\text{OH}^-\).
4. **Calculate New Concentrations:**
- Use the total moles and total volume in liters to find the molarity of each ion in the combined solution.
This calculation involves basic chemistry concepts like concentrations, moles, and solution mixing, and is often used to teach the principles of solution preparation and dilution.
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