42. A large insurance agency provides services to a number of customers who have purchased both a homeowner's policy and an automobile policy. For each type of policy, a deductible amount must be specified. Let x denote the homeowner's deductible amount and y denote the automobile deductible amount for a customer who has both types of poli- cies. The joint mass function of x and y is as follows: y auto f(x, y) 250 500 200 .20 .10 .20 me 500 .05 .15 30

MATLAB: An Introduction with Applications
6th Edition
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Author:Amos Gilat
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f(x,y)

y

 

0

250

500

x

200

0.20

0.10

0.20

 

500

0.05

0.15

0.30

The marginal mass function of x is

x

200

500

f ( x )

0.5

0.5

The marginal mass function of y is

y

0

250

500

f ( y )

0.25

0.25

0.5

Refer to Exercise 42. Compute the covariance between \( x \) and \( y \) and then the value of the population correlation coefficient. Do these two variables appear to be strongly related? Explain.
Transcribed Image Text:Refer to Exercise 42. Compute the covariance between \( x \) and \( y \) and then the value of the population correlation coefficient. Do these two variables appear to be strongly related? Explain.
**Title: Understanding Deductible Amounts in Insurance Policies**

**Introduction:**

A large insurance agency provides services to numerous customers who have purchased both a homeowner’s policy and an automobile policy. For each type of policy, a deductible amount must be specified. This section explores how these deductible amounts are determined and their implications.

**Notation:**

- Let \( x \) denote the homeowner’s deductible amount.
- Let \( y \) denote the automobile deductible amount.

**Joint Mass Function:**

For a customer who has both types of policies, the joint mass function of \( x \) and \( y \) is provided in the following table. This function helps us understand the probability distribution of various deductible scenarios:

\[
\begin{array}{c|ccc}
f(x, y) & y = 0 & y = 250 & y = 500 \\
\hline
x = 200 & 0.20 & 0.10 & 0.20 \\
x = 500 & 0.05 & 0.15 & 0.30 \\
\end{array}
\]

**Explanation of the Table:**

- The rows represent the different homeowner’s deductible amounts (\( x = 200 \) or \( x = 500 \)).
- The columns represent the different automobile deductible amounts (\( y = 0 \), \( y = 250 \), \( y = 500 \)).
- Each cell in the table denotes \( f(x, y) \), the joint probability of a customer having the specified combination of homeowner’s and automobile deductible amounts.

**Key Insights:**

- A customer with a homeowner’s deductible of $200 and an automobile deductible of $0 is quite likely, with a probability of 0.20.
- A higher homeowner’s deductible of $500, alongside an automobile deductible of $500, also appears to be common, with a probability of 0.30.
- These probabilities depict the risk distribution and can influence premium calculations for bundled insurance policies.

**Conclusion:**

Understanding this joint mass function is crucial for both insurance providers and customers. It aids in comprehending how deductible choices impact overall insurance costs and risk management strategies.
Transcribed Image Text:**Title: Understanding Deductible Amounts in Insurance Policies** **Introduction:** A large insurance agency provides services to numerous customers who have purchased both a homeowner’s policy and an automobile policy. For each type of policy, a deductible amount must be specified. This section explores how these deductible amounts are determined and their implications. **Notation:** - Let \( x \) denote the homeowner’s deductible amount. - Let \( y \) denote the automobile deductible amount. **Joint Mass Function:** For a customer who has both types of policies, the joint mass function of \( x \) and \( y \) is provided in the following table. This function helps us understand the probability distribution of various deductible scenarios: \[ \begin{array}{c|ccc} f(x, y) & y = 0 & y = 250 & y = 500 \\ \hline x = 200 & 0.20 & 0.10 & 0.20 \\ x = 500 & 0.05 & 0.15 & 0.30 \\ \end{array} \] **Explanation of the Table:** - The rows represent the different homeowner’s deductible amounts (\( x = 200 \) or \( x = 500 \)). - The columns represent the different automobile deductible amounts (\( y = 0 \), \( y = 250 \), \( y = 500 \)). - Each cell in the table denotes \( f(x, y) \), the joint probability of a customer having the specified combination of homeowner’s and automobile deductible amounts. **Key Insights:** - A customer with a homeowner’s deductible of $200 and an automobile deductible of $0 is quite likely, with a probability of 0.20. - A higher homeowner’s deductible of $500, alongside an automobile deductible of $500, also appears to be common, with a probability of 0.30. - These probabilities depict the risk distribution and can influence premium calculations for bundled insurance policies. **Conclusion:** Understanding this joint mass function is crucial for both insurance providers and customers. It aids in comprehending how deductible choices impact overall insurance costs and risk management strategies.
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