42. A large insurance agency provides services to a number of customers who have purchased both a homeowner's policy and an automobile policy. For each type of policy, a deductible amount must be specified. Let x denote the homeowner's deductible amount and y denote the automobile deductible amount for a customer who has both types of poli- cies. The joint mass function of x and y is as follows: y auto f(x, y) 250 500 200 .20 .10 .20 me 500 .05 .15 30
42. A large insurance agency provides services to a number of customers who have purchased both a homeowner's policy and an automobile policy. For each type of policy, a deductible amount must be specified. Let x denote the homeowner's deductible amount and y denote the automobile deductible amount for a customer who has both types of poli- cies. The joint mass function of x and y is as follows: y auto f(x, y) 250 500 200 .20 .10 .20 me 500 .05 .15 30
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
f(x,y) |
y |
|||
0 |
250 |
500 |
||
x |
200 |
0.20 |
0.10 |
0.20 |
500 |
0.05 |
0.15 |
0.30 |
The marginal mass
x |
200 |
500 |
f ( x ) |
0.5 |
0.5 |
The marginal mass function of y is
y |
0 |
250 |
500 |
f ( y ) |
0.25 |
0.25 |
0.5 |

Transcribed Image Text:Refer to Exercise 42. Compute the covariance between \( x \) and \( y \) and then the value of the population correlation coefficient. Do these two variables appear to be strongly related? Explain.
![**Title: Understanding Deductible Amounts in Insurance Policies**
**Introduction:**
A large insurance agency provides services to numerous customers who have purchased both a homeowner’s policy and an automobile policy. For each type of policy, a deductible amount must be specified. This section explores how these deductible amounts are determined and their implications.
**Notation:**
- Let \( x \) denote the homeowner’s deductible amount.
- Let \( y \) denote the automobile deductible amount.
**Joint Mass Function:**
For a customer who has both types of policies, the joint mass function of \( x \) and \( y \) is provided in the following table. This function helps us understand the probability distribution of various deductible scenarios:
\[
\begin{array}{c|ccc}
f(x, y) & y = 0 & y = 250 & y = 500 \\
\hline
x = 200 & 0.20 & 0.10 & 0.20 \\
x = 500 & 0.05 & 0.15 & 0.30 \\
\end{array}
\]
**Explanation of the Table:**
- The rows represent the different homeowner’s deductible amounts (\( x = 200 \) or \( x = 500 \)).
- The columns represent the different automobile deductible amounts (\( y = 0 \), \( y = 250 \), \( y = 500 \)).
- Each cell in the table denotes \( f(x, y) \), the joint probability of a customer having the specified combination of homeowner’s and automobile deductible amounts.
**Key Insights:**
- A customer with a homeowner’s deductible of $200 and an automobile deductible of $0 is quite likely, with a probability of 0.20.
- A higher homeowner’s deductible of $500, alongside an automobile deductible of $500, also appears to be common, with a probability of 0.30.
- These probabilities depict the risk distribution and can influence premium calculations for bundled insurance policies.
**Conclusion:**
Understanding this joint mass function is crucial for both insurance providers and customers. It aids in comprehending how deductible choices impact overall insurance costs and risk management strategies.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd627e045-d503-4693-9754-e0a854927fd5%2F0db4dd98-1d17-455d-ac01-5a3636eaabe4%2Fvwlm6v_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Understanding Deductible Amounts in Insurance Policies**
**Introduction:**
A large insurance agency provides services to numerous customers who have purchased both a homeowner’s policy and an automobile policy. For each type of policy, a deductible amount must be specified. This section explores how these deductible amounts are determined and their implications.
**Notation:**
- Let \( x \) denote the homeowner’s deductible amount.
- Let \( y \) denote the automobile deductible amount.
**Joint Mass Function:**
For a customer who has both types of policies, the joint mass function of \( x \) and \( y \) is provided in the following table. This function helps us understand the probability distribution of various deductible scenarios:
\[
\begin{array}{c|ccc}
f(x, y) & y = 0 & y = 250 & y = 500 \\
\hline
x = 200 & 0.20 & 0.10 & 0.20 \\
x = 500 & 0.05 & 0.15 & 0.30 \\
\end{array}
\]
**Explanation of the Table:**
- The rows represent the different homeowner’s deductible amounts (\( x = 200 \) or \( x = 500 \)).
- The columns represent the different automobile deductible amounts (\( y = 0 \), \( y = 250 \), \( y = 500 \)).
- Each cell in the table denotes \( f(x, y) \), the joint probability of a customer having the specified combination of homeowner’s and automobile deductible amounts.
**Key Insights:**
- A customer with a homeowner’s deductible of $200 and an automobile deductible of $0 is quite likely, with a probability of 0.20.
- A higher homeowner’s deductible of $500, alongside an automobile deductible of $500, also appears to be common, with a probability of 0.30.
- These probabilities depict the risk distribution and can influence premium calculations for bundled insurance policies.
**Conclusion:**
Understanding this joint mass function is crucial for both insurance providers and customers. It aids in comprehending how deductible choices impact overall insurance costs and risk management strategies.
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