4/18 The signboard truss is designed to support a horizontal wind load of 800 lb. A separate analysis shows that of this force is transmitted to the center connection at C and the rest is equally divided between D and B. Calculate the forces in members BE and BC. D 6' 800 lb 6' CE VB 6' G F A -6'- 3' PROBLEM 4/18 6'
4/18 The signboard truss is designed to support a horizontal wind load of 800 lb. A separate analysis shows that of this force is transmitted to the center connection at C and the rest is equally divided between D and B. Calculate the forces in members BE and BC. D 6' 800 lb 6' CE VB 6' G F A -6'- 3' PROBLEM 4/18 6'
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![**Problem 4/18**
The signboard truss is designed to support a horizontal wind load of 800 lb. A separate analysis shows that \(\frac{5}{8}\) of this force is transmitted to the center connection at \(C\) and the rest is equally divided between \(D\) and \(B\). Calculate the forces in members \(BE\) and \(BC\).
### Diagram Explanation:
The diagram presented displays a truss structure subjected to a horizontal wind load of 800 lb. The structure includes the following points and members:
- **Points:**
- **A** and **G**: Supports at the bottom of the truss.
- **B**, **C**, **D**, **E**, and **F**: Joints along the truss.
- **Members:**
- Vertical and diagonal beams (lines connected between the above points).
- The truss has multiple vertical segments each measuring 6 feet in height.
- There are horizontal segments between \(A\) and \(G\), \(G\) and \(F\), \(F\) and \(E\), and \(E\) and \(D\).
Vertically, the structure has a total height comprised of four 6-foot vertical segments (totaling 24 feet). Horizontally, the structure has segments measuring 6 feet between \(A\) and \(G\), and 3 feet between \(G\) and the point directly below \(F\).
### Steps for Calculation:
1. **Determine the force distribution:**
- According to the analysis, \(\frac{5}{8}\) of the 800 lb force is transmitted to point \(C\).
Force at \(C\):
\[
F_C = \left( \frac{5}{8} \right) \times 800 \, \text{lb} = 500 \, \text{lb}
\]
- The remaining force is \(\frac{3}{8}\) of 800 lb, which equals 300 lb.
Remaining force:
\[
800 \, \text{lb} - 500 \, \text{lb} = 300 \, \text{lb}
\]
- This remaining force is equally divided between points \(D\) and \(B\).
Force at \(D\) and \(B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf950827-7d70-472f-a52e-1d3c26fa2196%2Ff166f451-15df-49d4-a640-000ed7e67404%2Fm3b8ad_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 4/18**
The signboard truss is designed to support a horizontal wind load of 800 lb. A separate analysis shows that \(\frac{5}{8}\) of this force is transmitted to the center connection at \(C\) and the rest is equally divided between \(D\) and \(B\). Calculate the forces in members \(BE\) and \(BC\).
### Diagram Explanation:
The diagram presented displays a truss structure subjected to a horizontal wind load of 800 lb. The structure includes the following points and members:
- **Points:**
- **A** and **G**: Supports at the bottom of the truss.
- **B**, **C**, **D**, **E**, and **F**: Joints along the truss.
- **Members:**
- Vertical and diagonal beams (lines connected between the above points).
- The truss has multiple vertical segments each measuring 6 feet in height.
- There are horizontal segments between \(A\) and \(G\), \(G\) and \(F\), \(F\) and \(E\), and \(E\) and \(D\).
Vertically, the structure has a total height comprised of four 6-foot vertical segments (totaling 24 feet). Horizontally, the structure has segments measuring 6 feet between \(A\) and \(G\), and 3 feet between \(G\) and the point directly below \(F\).
### Steps for Calculation:
1. **Determine the force distribution:**
- According to the analysis, \(\frac{5}{8}\) of the 800 lb force is transmitted to point \(C\).
Force at \(C\):
\[
F_C = \left( \frac{5}{8} \right) \times 800 \, \text{lb} = 500 \, \text{lb}
\]
- The remaining force is \(\frac{3}{8}\) of 800 lb, which equals 300 lb.
Remaining force:
\[
800 \, \text{lb} - 500 \, \text{lb} = 300 \, \text{lb}
\]
- This remaining force is equally divided between points \(D\) and \(B\).
Force at \(D\) and \(B
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