٤/١Q2-A water-tight shield is prevented from overturning by means of woodenstruts AB (see figure) each having a circular cross-section 15 cm in diameter.The allowable stress for the material of the struts is 20 kg/cm2. Determine themaximum allowable distance between the struts. Answer: 1-88 m.4m3m

Given:Water-tight shield prevented from overturning by wooden struts AB.Struts have circular…

Answered: ٤/١ Q2-A water-tight shield is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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225 P= 8 P= 10 9,- 18 H3 2 (m) 1 (m) . 4.50 (m) 1.50 (m)
A steel pipe (D = 3.500 in.; d = 3.068 in.) supports a concentrated load of P = 617 lb as shown. The span length of the cantilever beam is L = 4 ft. Determine the magnitude of the maximum bending stress in the pipe. O 21.55 ksi O 13.81 ksi O 15.73 ksi O 24.04 ksi O 17.18 ksi L B P d Pipe cross section. D
mm on its side, just 2. A cantilever, made of a certain material, of 2 m length and square section fails in bending when a point load of N is placed at its free end. A beam of rectangular cross section, and made of same material, 150 mm wide and 300 mm deep, is simply supported over a span of 3 m. Calculate: (a) the stress at which the cantilever beam fails in kPa and (b) the maximum concentrated load that the beam can carry at its center without failure in kN. 2 m (a) Cantilever kN THIS |— 1.5 m —— 1.5 m—| (b) Simply supported beam 150 300
6.3 Design the beam below using the operating stresses method If the uniformly spread load is n= 10 20 km section width b = 300mm, permissible stresses 140MPa, c=10MPa = ignore the weight of the beam. W-20 kN/m 4m
"D.60. Compute the ultimate strength capacity of the positive moment beam design below. f'c= 28 MPa, fy= 414.6 MPa, bf= 760 mm, t= 85 mm, hw= 440 mm, bw = 420 mm ds= 10 mm, ct= 30 mm, cb = 35 mm. Steel bar details: compression side at top (single layer): 3 - 16 mm dia. , tension side (double- layered): upper layer is 4 - 28 mm dia. and lower layer is 4 - 28 mm dia." Use the editor to format your answer br Ct t Bar diameters and positioning in the figure given are just representations. Refer to the problem ds hw statement for the number of bars and bar diameters to use in your computation. 25 mm Cb bw
Problem 5: Replace the loading by an equivalent resultant force and couple moment at point O. 0.5 m 0.7 m F,=(-2 i+5j-3 k) kN 0.8 m F = (8 i– 2 k} kN
If the maximum allowable force (tensile or compressive) in members GF in the pin-connected truss shown is known to be 270 kN. Determine the maximum load P that can be applied to the truss. 6 m 6 m 6m 6m 6m Select one: OA.P= 90.00 KN OB. P = 270.00 KN OC.P = 405.00 KN OD.P = 180.00 KN OE.P = 135.00 KN P.
RUSH
For the given one bay- one story frame; wn=0.5 s, E=30000 MPa, I=3*107 mm4, S= I/c=2.5*105 mm3. Determine u0, the maximum dynamic deformation and maximum bending stress in the column. Neglect damping.

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