41 45 us 41 6as 9 Jolnt Foc Joint G Fer EM=0, FAB=-1825 08 (c) Foe sincus)- Ga5 =0 FOE= 883.983 08 CT) Foo EFy =o', FBF 5a5 08 E fAzo, - Fen - 883 983 cosCu5)=0 Joint F Foc: - Ga5 e Efy=d, - 585- JGA7056 Sin is- For

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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41
45
us
41
B GI
515.06
Joint D
Foc
Joint 3
Far
EM=o', FAB= -1825 08 (C )
EFy co', FBF= 525 08
-1
525.06
FoE sin(us)- GR5 =0
FOE = 883. 8838 (T)
Joint F
E Fnzo, - FeD - 883 983 cosCu5)=0
FoC: - 625 e8 (C)
Efy=0,
45
- 5R5 - 1697.056 sin 45-
FAF sinus =o
FAF
JointE
525.06
FEF
FAF=- 2439.518 b(C)
- FEF + CB83 339) oos Cus)0
1,
JFCE 987 s
FEF =+ '625
es (T)
625+1697.056 cosCus) - Fer- C-439. 618) os 45-0
- FCE - Caa) sincus)=o
FCE = -625
FeF= 3550 eb CT)
Tointc
Fer
Gas
- G25 - 575+ FoF sincus)-o
FCF: 1697.05c e8 (T)
FBC
575.00
- Fec - C25 - 1697.056 msCu5)=0
+ Fac = -1825 28 (C)
Transcribed Image Text:41 45 us 41 B GI 515.06 Joint D Foc Joint 3 Far EM=o', FAB= -1825 08 (C ) EFy co', FBF= 525 08 -1 525.06 FoE sin(us)- GR5 =0 FOE = 883. 8838 (T) Joint F E Fnzo, - FeD - 883 983 cosCu5)=0 FoC: - 625 e8 (C) Efy=0, 45 - 5R5 - 1697.056 sin 45- FAF sinus =o FAF JointE 525.06 FEF FAF=- 2439.518 b(C) - FEF + CB83 339) oos Cus)0 1, JFCE 987 s FEF =+ '625 es (T) 625+1697.056 cosCus) - Fer- C-439. 618) os 45-0 - FCE - Caa) sincus)=o FCE = -625 FeF= 3550 eb CT) Tointc Fer Gas - G25 - 575+ FoF sincus)-o FCF: 1697.05c e8 (T) FBC 575.00 - Fec - C25 - 1697.056 msCu5)=0 + Fac = -1825 28 (C)
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Erase
Problem #2:
Note: Replace all zero digits of your ID
number by number "2"
4 ft
Use
X = Last 3 digits of ID number
4 ft
4 ft
-4 ft
Y = Last 2 digits of ID number
450 + Y (Ib) 500 + Y (Ib)
550 + Y (Ib)
A = 4th digit of ID number
B = 5th digit of ID number
C= 6th digit of ID number
11. Determine the magnitude of the force in member GF. (Ib)
12. Determine the magnitude of the force in member FE. (Ib)
13. Determine the magnitude of the force in member AF. (Ib)
14. Determine the magnitude of the force in member BF. (Ib)
15. Determine the magnitude of the force in member CF. (Ib)
e.g.,
ID # = 12-3456-789
X= 789
Y = 89
16. Determine the magnitude of the force in member CE. (Ib)
A = 4
17. Determine the magnitude of the force in member DE. (Ib)
B = 5
18. Determine the magnitude of the force in member AB. (Ib)
C = 6
19. Determine the magnitude of the force in member BC. (Ib)
20. Determine the magnitude of the force in member CD. (Ib)
357 pm
18/11/2021
A 4 ENG
30°C Rain showers
P Type here to search
+
Transcribed Image Text:Page view A" Read aloud O Add text V Draw I Highlight Erase Problem #2: Note: Replace all zero digits of your ID number by number "2" 4 ft Use X = Last 3 digits of ID number 4 ft 4 ft -4 ft Y = Last 2 digits of ID number 450 + Y (Ib) 500 + Y (Ib) 550 + Y (Ib) A = 4th digit of ID number B = 5th digit of ID number C= 6th digit of ID number 11. Determine the magnitude of the force in member GF. (Ib) 12. Determine the magnitude of the force in member FE. (Ib) 13. Determine the magnitude of the force in member AF. (Ib) 14. Determine the magnitude of the force in member BF. (Ib) 15. Determine the magnitude of the force in member CF. (Ib) e.g., ID # = 12-3456-789 X= 789 Y = 89 16. Determine the magnitude of the force in member CE. (Ib) A = 4 17. Determine the magnitude of the force in member DE. (Ib) B = 5 18. Determine the magnitude of the force in member AB. (Ib) C = 6 19. Determine the magnitude of the force in member BC. (Ib) 20. Determine the magnitude of the force in member CD. (Ib) 357 pm 18/11/2021 A 4 ENG 30°C Rain showers P Type here to search +
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