41 45 us 41 6as 9 Jolnt Foc Joint G Fer EM=0, FAB=-1825 08 (c) Foe sincus)- Ga5 =0 FOE= 883.983 08 CT) Foo EFy =o', FBF 5a5 08 E fAzo, - Fen - 883 983 cosCu5)=0 Joint F Foc: - Ga5 e Efy=d, - 585- JGA7056 Sin is- For
41 45 us 41 6as 9 Jolnt Foc Joint G Fer EM=0, FAB=-1825 08 (c) Foe sincus)- Ga5 =0 FOE= 883.983 08 CT) Foo EFy =o', FBF 5a5 08 E fAzo, - Fen - 883 983 cosCu5)=0 Joint F Foc: - Ga5 e Efy=d, - 585- JGA7056 Sin is- For
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Someone answer it from bartebly . Please encircle the final answers thank you
![41
45
us
41
B GI
515.06
Joint D
Foc
Joint 3
Far
EM=o', FAB= -1825 08 (C )
EFy co', FBF= 525 08
-1
525.06
FoE sin(us)- GR5 =0
FOE = 883. 8838 (T)
Joint F
E Fnzo, - FeD - 883 983 cosCu5)=0
FoC: - 625 e8 (C)
Efy=0,
45
- 5R5 - 1697.056 sin 45-
FAF sinus =o
FAF
JointE
525.06
FEF
FAF=- 2439.518 b(C)
- FEF + CB83 339) oos Cus)0
1,
JFCE 987 s
FEF =+ '625
es (T)
625+1697.056 cosCus) - Fer- C-439. 618) os 45-0
- FCE - Caa) sincus)=o
FCE = -625
FeF= 3550 eb CT)
Tointc
Fer
Gas
- G25 - 575+ FoF sincus)-o
FCF: 1697.05c e8 (T)
FBC
575.00
- Fec - C25 - 1697.056 msCu5)=0
+ Fac = -1825 28 (C)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b8e785a-51b3-4f44-9877-9558213b64d3%2Fd2761e47-f63d-4922-be20-317dc8db78b0%2F6cs4kzl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:41
45
us
41
B GI
515.06
Joint D
Foc
Joint 3
Far
EM=o', FAB= -1825 08 (C )
EFy co', FBF= 525 08
-1
525.06
FoE sin(us)- GR5 =0
FOE = 883. 8838 (T)
Joint F
E Fnzo, - FeD - 883 983 cosCu5)=0
FoC: - 625 e8 (C)
Efy=0,
45
- 5R5 - 1697.056 sin 45-
FAF sinus =o
FAF
JointE
525.06
FEF
FAF=- 2439.518 b(C)
- FEF + CB83 339) oos Cus)0
1,
JFCE 987 s
FEF =+ '625
es (T)
625+1697.056 cosCus) - Fer- C-439. 618) os 45-0
- FCE - Caa) sincus)=o
FCE = -625
FeF= 3550 eb CT)
Tointc
Fer
Gas
- G25 - 575+ FoF sincus)-o
FCF: 1697.05c e8 (T)
FBC
575.00
- Fec - C25 - 1697.056 msCu5)=0
+ Fac = -1825 28 (C)
![Page view
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Problem #2:
Note: Replace all zero digits of your ID
number by number "2"
4 ft
Use
X = Last 3 digits of ID number
4 ft
4 ft
-4 ft
Y = Last 2 digits of ID number
450 + Y (Ib) 500 + Y (Ib)
550 + Y (Ib)
A = 4th digit of ID number
B = 5th digit of ID number
C= 6th digit of ID number
11. Determine the magnitude of the force in member GF. (Ib)
12. Determine the magnitude of the force in member FE. (Ib)
13. Determine the magnitude of the force in member AF. (Ib)
14. Determine the magnitude of the force in member BF. (Ib)
15. Determine the magnitude of the force in member CF. (Ib)
e.g.,
ID # = 12-3456-789
X= 789
Y = 89
16. Determine the magnitude of the force in member CE. (Ib)
A = 4
17. Determine the magnitude of the force in member DE. (Ib)
B = 5
18. Determine the magnitude of the force in member AB. (Ib)
C = 6
19. Determine the magnitude of the force in member BC. (Ib)
20. Determine the magnitude of the force in member CD. (Ib)
357 pm
18/11/2021
A 4 ENG
30°C Rain showers
P Type here to search
+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b8e785a-51b3-4f44-9877-9558213b64d3%2Fd2761e47-f63d-4922-be20-317dc8db78b0%2Fjq9n6x8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Page view
A" Read aloud
O Add text
V Draw
I Highlight
Erase
Problem #2:
Note: Replace all zero digits of your ID
number by number "2"
4 ft
Use
X = Last 3 digits of ID number
4 ft
4 ft
-4 ft
Y = Last 2 digits of ID number
450 + Y (Ib) 500 + Y (Ib)
550 + Y (Ib)
A = 4th digit of ID number
B = 5th digit of ID number
C= 6th digit of ID number
11. Determine the magnitude of the force in member GF. (Ib)
12. Determine the magnitude of the force in member FE. (Ib)
13. Determine the magnitude of the force in member AF. (Ib)
14. Determine the magnitude of the force in member BF. (Ib)
15. Determine the magnitude of the force in member CF. (Ib)
e.g.,
ID # = 12-3456-789
X= 789
Y = 89
16. Determine the magnitude of the force in member CE. (Ib)
A = 4
17. Determine the magnitude of the force in member DE. (Ib)
B = 5
18. Determine the magnitude of the force in member AB. (Ib)
C = 6
19. Determine the magnitude of the force in member BC. (Ib)
20. Determine the magnitude of the force in member CD. (Ib)
357 pm
18/11/2021
A 4 ENG
30°C Rain showers
P Type here to search
+
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