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400L tank initially has 10OL saltwater with 50g salt dissolved. In flows 5L/min saltwater with [salt]=2g/L, Outflow of the mixture at salt]=Q/V has rate also 5L/mir Write and solve the IVP for Q(t)= quantity of salt in the mixing tank.

400L tank initially has 10OL saltwater with 50g salt dissolved. In flows 5L/min saltwater with [salt]=2g/L, Outflow of the mixture at salt]=Q/V has rate also 5L/mir Write and solve the IVP for Q(t)= quantity of salt in the mixing tank.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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400L tank initially has 10OL saltwater with 50g salt dissolved. In flows 5L/min saltwater with [salt]=2g/L, Outflow of the mixture at [salt]=Q/V has rate also 5L/min Write and solve the IVP for Q(t)= quantity of salt in the mixing tank. Q (t) = 200 – 100e 0.02t OQ (t) = 400 – 250e -0.05t OQ (t) = 200 + 150e-0.05t OQ(t) = 400 + 150e0.05t OQ(t) 800 – 600e0.012
Transcribed Image Text:400L tank initially has 10OL saltwater with 50g salt dissolved. In flows 5L/min saltwater with [salt]=2g/L, Outflow of the mixture at [salt]=Q/V has rate also 5L/min Write and solve the IVP for Q(t)= quantity of salt in the mixing tank. Q (t) = 200 – 100e 0.02t OQ (t) = 400 – 250e -0.05t OQ (t) = 200 + 150e-0.05t OQ(t) = 400 + 150e0.05t OQ(t) 800 – 600e0.012
Q(t) = 200 100e 0.02t Q(t) = 400 250e_0.05t Q (t) = 200 + 150e 0.054 Q(t) = 0.051 400 150eº CQ(1) = 800 600e 0.01t OQ(t) = 200 0.05t 150e
Transcribed Image Text:Q(t) = 200 100e 0.02t Q(t) = 400 250e_0.05t Q (t) = 200 + 150e 0.054 Q(t) = 0.051 400 150eº CQ(1) = 800 600e 0.01t OQ(t) = 200 0.05t 150e
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