What is the IR and HNMRAndCNMR and mass IR Spectrum(quid fim)40001008060ETTE% of base peak3000204013C NMR Spectrum(50.0 MHz, CDC, solution)8091DEPT CH CH₂ CHproton decoupled200¹H NMR Spectrum(200 MHz, CDCI, solution)10982000v (cm¹)120m/e160ww16000.08001200Mass Spectrum0.51.0C₂H,Br2801607M170/1722001206240expansion140expansion1405solvent1301308041.5Problem 24UV spectrum0.917 mg/10 mispath length 0 20 cmsolvent hexaneabsorbance200ppmppm403250 300λ (nm)2013508 (ppm)TMS08 (ppm

Please find your solution below : Spectroscopy is the study of absorption or emission of radiation…

4000 100 во IR Spectrum (quid fim) 2828 60 20 % of base peak 3000 40 80 13C NMR Spectrum (50.0 MHz, CDC), solution) 91 DEPT CH CH CHt proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 v (cm¹) M 170/172 120 ww m 0.0 1600 800 1200 Mass Spectrum 0.5 1.0 C,H,Br 1.5 280 160 160 m/e 7 200 120 6 240 expansion 140 expansion 140 1 solvent 5 130 130 1 80 4 Problem 24 UV spectrum 0.917 mg/10 mis path length 0 20 cm solvent hexane 300 200 ppm ppm 40 3 250 2 (nm) 2 0 350 8 (ppm) TMS L L 0 8 (ppm 1

4000 100 во IR Spectrum (quid fim) 2828 60 20 % of base peak 3000 40 80 13C NMR Spectrum (50.0 MHz, CDC), solution) 91 DEPT CH CH CHt proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 v (cm¹) M 170/172 120 ww m 0.0 1600 800 1200 Mass Spectrum 0.5 1.0 C,H,Br 1.5 280 160 160 m/e 7 200 120 6 240 expansion 140 expansion 140 1 solvent 5 130 130 1 80 4 Problem 24 UV spectrum 0.917 mg/10 mis path length 0 20 cm solvent hexane 300 200 ppm ppm 40 3 250 2 (nm) 2 0 350 8 (ppm) TMS L L 0 8 (ppm 1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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