4000 100 во IR Spectrum (quid fim) 2828 60 20 % of base peak 3000 40 80 13C NMR Spectrum (50.0 MHz, CDC), solution) 91 DEPT CH CH CHt proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 v (cm¹) M 170/172 120 ww m 0.0 1600 800 1200 Mass Spectrum 0.5 1.0 C,H,Br 1.5 280 160 160 m/e 7 200 120 6 240 expansion 140 expansion 140 1 solvent 5 130 130 1 80 4 Problem 24 UV spectrum 0.917 mg/10 mis path length 0 20 cm solvent hexane 300 200 ppm ppm 40 3 250 2 (nm) 2 0 350 8 (ppm) TMS L L 0 8 (ppm 1
4000 100 во IR Spectrum (quid fim) 2828 60 20 % of base peak 3000 40 80 13C NMR Spectrum (50.0 MHz, CDC), solution) 91 DEPT CH CH CHt proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 v (cm¹) M 170/172 120 ww m 0.0 1600 800 1200 Mass Spectrum 0.5 1.0 C,H,Br 1.5 280 160 160 m/e 7 200 120 6 240 expansion 140 expansion 140 1 solvent 5 130 130 1 80 4 Problem 24 UV spectrum 0.917 mg/10 mis path length 0 20 cm solvent hexane 300 200 ppm ppm 40 3 250 2 (nm) 2 0 350 8 (ppm) TMS L L 0 8 (ppm 1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
What is the IR and HNMRAndCNMR and mass
Transcribed Image Text:IR Spectrum
(quid fim)
4000
100
80
60
ETTE
% of base peak
3000
20
40
13C NMR Spectrum
(50.0 MHz, CDC, solution)
80
91
DEPT CH CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
10
9
8
2000
v (cm¹)
120
m/e
160
ww
1600
0.0
800
1200
Mass Spectrum
0.5
1.0
C₂H,Br
280
160
7
M
170/172
200
120
6
240
expansion
140
expansion
140
5
solvent
130
130
80
4
1.5
Problem 24
UV spectrum
0.917 mg/10 mis
path length 0 20 cm
solvent hexane
absorbance
200
ppm
ppm
40
3
250 300
λ (nm)
2
0
1
350
8 (ppm)
TMS
0
8 (ppm
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