4000 100 8898 IR Spectrum (liquid film) 60 % of base peak 3000 800 V (cm¹) M Mass Spectrum CHyOz 80 120 160 200 240 280 m/e DEPT CH₂ CH CH solvent 120 80 40 13C NMR Spectrum (100.0 MHz, CDCI, solution) proton decoupled 200 ¹H NMR Spectrum (400 MHz, CDCI, solution) 10 9 8 2000 160 3.8 7 1600 expansion 1200 3.6 ppm L 6 5 4 3 Problem 80 No significant UV absorption above 220 nm 40 1.8 J 2 0 expansion 1.6 ppm 1 1 186 8 (ppm) TMS L 0 8 (ppm)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass
IR Spectrum
(liquid film)
L
4000
100
3000
% of base peak
80
60 s
40
20
40
80
13C NMR Spectrum
(1000 MHz, CDCI, solution)
proton decoupled
200
¹H NMR Spectrum
(400 MHz, CDCI, solution)
10
9
www
2000
v (cm¹)
M-88
1600
120 160 200
m/e
DEPT CH₂ CH₂ CH
120
160
expansion
3.8 3.6 ppm
8 7 6
800
Mass Spectrum
C4H802
280
1200
240
5
solvent
80
Problem 80
No significant UV
absorption above 220 m
4 3
40
1.8
expansion
08 (ppm)
1.6 ppm
£
2
186
J
1
TMS
L
0
8 (ppm)
169
Transcribed Image Text:IR Spectrum (liquid film) L 4000 100 3000 % of base peak 80 60 s 40 20 40 80 13C NMR Spectrum (1000 MHz, CDCI, solution) proton decoupled 200 ¹H NMR Spectrum (400 MHz, CDCI, solution) 10 9 www 2000 v (cm¹) M-88 1600 120 160 200 m/e DEPT CH₂ CH₂ CH 120 160 expansion 3.8 3.6 ppm 8 7 6 800 Mass Spectrum C4H802 280 1200 240 5 solvent 80 Problem 80 No significant UV absorption above 220 m 4 3 40 1.8 expansion 08 (ppm) 1.6 ppm £ 2 186 J 1 TMS L 0 8 (ppm) 169
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