400 kN 800 kN 6 m D 3 m A 3 m 6 m E 6 m 200 kN 200 kN B.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
1. Compute the force in members BD, CD, and CE by the method of sections.

Transcribed Image Text:The image is a diagram of a truss structure commonly used in engineering to distribute loads. Here's a detailed explanation:
**Truss Structure Diagram:**
- **Points and Members:**
- The truss consists of interconnected members joined at nodes labeled A, B, C, D, E, and F.
- The members are the straight lines connecting these nodes.
- **Loads Applied:**
- A vertical load of 400 kN is applied downward at node B.
- A vertical load of 800 kN is applied downward at node D.
- Two vertical loads of 200 kN each are applied downward at nodes C and E.
- **Supports:**
- Node A is supported by a pin, allowing rotation but no horizontal or vertical movement.
- Node F is supported by a roller, allowing horizontal movement but not vertical movement.
- **Distances Between Nodes:**
- The horizontal distance between nodes A and C is 3 meters.
- The horizontal distance between nodes C and E is 6 meters.
- The horizontal distance between nodes E and F is 6 meters.
- The vertical distance between nodes C and B is 6 meters.
- The vertical distance between nodes E and D is 3 meters.
This diagram illustrates how forces are applied and distributed within a truss, making it useful for analyzing structural stability and load-bearing capacity in engineering projects.
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