40. Consider the events A = {wears shorts} is more likely to happen (a) Which has the higher probability, {A or B) or (A and B)? Explain. A or B since it is a union it (b) Based on your intuition, are the events A and B disjoint? Explain. No Since there is likely to be a probability of P(Aand B) (c) Based on your intuition, are the events A and B independent? Explain. Yes Since A will not effect B + vise versa and R with P(A) = 0.7 and P(B) = 0.4. (AB)

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### Educational Content: Probability and Event Analysis

#### Exercise 40: Analyzing Clothing Events
Consider the events:
- \( A = \) wears shorts
- \( B = \) wears a sweatshirt

- **(a)** Which has the higher probability, \( (A \text{ or } B) \) or \( (A \text{ and } B) \)? Explain.  
  *Explanation:* \( A \text{ or } B \) since if so a union it is more likely to happen.
  
- **(b)** Based on your intuition, are the events \( A \) and \( B \) disjoint? Explain.  
  *Explanation:* No, since there is likely to be a probability of \( P(A \text{ and } B) \).

- **(c)** Based on your intuition, are the events \( A \) and \( B \) independent? Explain.  
  *Explanation:* No effect of wearing \( A \) with wearing \( B \), hence not independent.

#### Exercise 41: Probability Assignment
Consider two disjoint (or mutually exclusive) events \( A \) and \( B \) with \( P(A) = 0.7 \) and \( P(B) = 0.4 \). Are these probabilities correctly assigned?

- **Hint:** Calculate \( P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \)
  - Calculation: \( 0.7 + 0.4 - 0 = 1.1 \)

#### Exercise 42: Coin Toss Analysis
The table below represents the theoretical outcomes of tossing a coin twice:

|              | Second Toss Heads | Second Toss Tails | Row Totals |
|--------------|-------------------|-------------------|------------|
| First Toss Heads | 25                | 25                | 50         |
| First Toss Tails | 25                | 25                | 50         |
| Column Totals | 50                | 50                | 100        |

- **(a)** Are getting heads on the first toss and heads on the second toss mutually exclusive events?  
  *Explanation:* No, they can occur simultaneously. Probability of each is calculated by considering all possible outcomes.

- **(b)** Are getting heads on the first toss and heads on the second toss independent events?  
  *Explanation
Transcribed Image Text:### Educational Content: Probability and Event Analysis #### Exercise 40: Analyzing Clothing Events Consider the events: - \( A = \) wears shorts - \( B = \) wears a sweatshirt - **(a)** Which has the higher probability, \( (A \text{ or } B) \) or \( (A \text{ and } B) \)? Explain. *Explanation:* \( A \text{ or } B \) since if so a union it is more likely to happen. - **(b)** Based on your intuition, are the events \( A \) and \( B \) disjoint? Explain. *Explanation:* No, since there is likely to be a probability of \( P(A \text{ and } B) \). - **(c)** Based on your intuition, are the events \( A \) and \( B \) independent? Explain. *Explanation:* No effect of wearing \( A \) with wearing \( B \), hence not independent. #### Exercise 41: Probability Assignment Consider two disjoint (or mutually exclusive) events \( A \) and \( B \) with \( P(A) = 0.7 \) and \( P(B) = 0.4 \). Are these probabilities correctly assigned? - **Hint:** Calculate \( P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \) - Calculation: \( 0.7 + 0.4 - 0 = 1.1 \) #### Exercise 42: Coin Toss Analysis The table below represents the theoretical outcomes of tossing a coin twice: | | Second Toss Heads | Second Toss Tails | Row Totals | |--------------|-------------------|-------------------|------------| | First Toss Heads | 25 | 25 | 50 | | First Toss Tails | 25 | 25 | 50 | | Column Totals | 50 | 50 | 100 | - **(a)** Are getting heads on the first toss and heads on the second toss mutually exclusive events? *Explanation:* No, they can occur simultaneously. Probability of each is calculated by considering all possible outcomes. - **(b)** Are getting heads on the first toss and heads on the second toss independent events? *Explanation
Expert Solution
Step 1: Determine the given data

Since you have asked multiple questions, we will solve the first question for you. If you want any specific question to be solved, then please specify the question number or post only that question.

The events are given as follows:

A={wears shorts}

B={wears a sweatshirt}

The probabilities for the events, {A or B} and {A and B} is defined as follows:

P(A or B)= probability that an individual wears shorts or a sweatshirt.

P(A and B)= probability that an individual wears shorts and a sweatshirt.



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