40. A 92-kg baseball player slides into second base. The coelll- cient of kinetic friction between the player and the ground is Mx=0.61. (a) What is the magnitude of the frictional force? (b) If the player comes to rest after 1.2 s, what is his initial speed? horizontal floor of an ele-

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#40

**Educational Content: Physics Problem Solving**

**Problem 39**
A 600-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are \( \mu_s = 0.760 \) and \( \mu_k = 0.410 \), respectively. What horizontal pushing force is required to:  
(a) just start the crate moving and  
(b) slide the crate across the dock at a constant speed?

**Problem 40**
A 92-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is \( \mu_k = 0.61 \).  
(a) What is the magnitude of the frictional force?  
(b) If the player comes to rest after sliding 3.5 m, what was his initial speed?

**Problem 41**
A 600-kg box is sliding across the horizontal floor of an elevator. The coefficient of kinetic friction between the box and the floor is 0.360. Determine the kinetic frictional force that acts on the box when the elevator is:  
(a) stationary  
(b) accelerating upward with an acceleration whose magnitude is \( 1.20 \, \text{m/s}^2 \), and  
(c) accelerating downward with an acceleration whose magnitude is \( 1.20 \, \text{m/s}^2 \).

**Analysis and Explanation:**

- **Friction in Problem 39:**  
  - Static friction (\( \mu_s \)) determines the force necessary to start moving an object.
  - Kinetic friction (\( \mu_k \)) relates to the force needed to maintain constant speed once in motion.

- **Frictional Force in Problem 40:**  
  - Kinetic friction opposes the sliding motion of the player.
  - Energy considerations (kinetic energy and work done by friction) can determine the player’s initial speed.

- **Friction in an Accelerating System (Problem 41):**  
  - Kinetic friction force depends on normal force, which changes with the elevator’s acceleration.  
  - When the elevator accelerates, the effective gravitational force changes, altering the friction.
Transcribed Image Text:**Educational Content: Physics Problem Solving** **Problem 39** A 600-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are \( \mu_s = 0.760 \) and \( \mu_k = 0.410 \), respectively. What horizontal pushing force is required to: (a) just start the crate moving and (b) slide the crate across the dock at a constant speed? **Problem 40** A 92-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is \( \mu_k = 0.61 \). (a) What is the magnitude of the frictional force? (b) If the player comes to rest after sliding 3.5 m, what was his initial speed? **Problem 41** A 600-kg box is sliding across the horizontal floor of an elevator. The coefficient of kinetic friction between the box and the floor is 0.360. Determine the kinetic frictional force that acts on the box when the elevator is: (a) stationary (b) accelerating upward with an acceleration whose magnitude is \( 1.20 \, \text{m/s}^2 \), and (c) accelerating downward with an acceleration whose magnitude is \( 1.20 \, \text{m/s}^2 \). **Analysis and Explanation:** - **Friction in Problem 39:** - Static friction (\( \mu_s \)) determines the force necessary to start moving an object. - Kinetic friction (\( \mu_k \)) relates to the force needed to maintain constant speed once in motion. - **Frictional Force in Problem 40:** - Kinetic friction opposes the sliding motion of the player. - Energy considerations (kinetic energy and work done by friction) can determine the player’s initial speed. - **Friction in an Accelerating System (Problem 41):** - Kinetic friction force depends on normal force, which changes with the elevator’s acceleration. - When the elevator accelerates, the effective gravitational force changes, altering the friction.
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