[40] Your friend, Velma, has lost her glasses and is having difficulty seeing because of her hyperopia (farsightedness). Discuss whether there is any way a magnifying glass (convex lens) with an 8.5 cm focal length will help her to see. Include ray diagrams to illustrate whether the magnifying glass helps or not. You may include sample calculations as evidence of your conclusions.
Q: 1) A 3.5 cm tall object is 12 cm away from a lens with focal length 32 cm. a) Calculate the height…
A: a) To calculate the height of the image formed by the lens, we can use the thin lens equation: 1/f =…
Q: 8. A diverging lens (f₁ = -11.0 cm) is located 42.0 cm to the left of a converging lens (f₂ = 23.5…
A: The given two questions are separate questions.As you have posted multiple questions so, as per our…
Q: A thin, convergent lens has a focal length of 8.10 cm. If the object distance is 30.0 cm, find the…
A: Given: The focal length of the converging lens is 8.1 cm. The distance of the object is 30 cm.
Q: 2. An object that is 3.0 cm tall is placed 6.0 cm in front of a thin diverging lens with a focal…
A: The height of the object: The object distance: (The negative sign indicates that the object is…
Q: 3. A convex (converging) lens has a focal length of 15.0 cm. Where on the lens axis should an object…
A:
Q: A convex lens is set up on a table. On one side is an illuminated object of size 8 cm that is 41 cm…
A:
Q: In an optics experiment you are trying to set up a two-lens system that will produce an image twice…
A: "Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…
Q: The focal length of a diverging lens is negative. If f = −25 cm for a particular diverging lens,…
A:
Q: The far point of a certain myopic eye is 50 cm in front of the eye. Find the focal length and power…
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Q: The radii of curvature of the surfaces of a thin meniscus convex lens are r1 =28.0 cm and r2 = 12.0…
A: The radii of curvature of the surfaces of a thin meniscus convex lens are r1 =28.0 cm and r2 = 12.0…
Q: You have a concave (diverging) lens with a −35 cm focal length. The magnification produced by the…
A: The u-v-f relation for lens is 1v-1u=1f ....(1) The magnification is m=vu .....(2) Here…
Q: An object of height 3.2 cm is placed at 22 cm in front of a diverging lens of focal length, f = - 16…
A: The height of the object is given as, ho=3.2 cm, The distance between the object and the diverging…
Q: . A 4.0-cm object is placed 30.0 cm from a converging lens that has a focal length of 10.0 cm as…
A: Given: The distance of the object is 30 cm. The height of the object is 3 cm. The focal length of…
Q: 10. (a) Two lenses are separated by 35 cm. An object is 20 cm to the left of the first lens. (i) The…
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Q: What is the focal length of a drop (ball) of benzene (n = 1.501) of radius 2 mm. Determine the…
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Q: 3. An object is 16.0 cm to the left of a lens. The lens forms an image 36.0 cm to the right of the…
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Q: A convex lens is set up on a table. On one side is an illuminated object of size 5 cm that is 28 cm…
A:
Q: 9. A diverging lens (f, = -10.5 cm) is located 54.0 cm to the left of a converging lens (f2 = 20.0…
A: Recall 1v-1u=1fWhere v=image distance u=object distance f=focal length
Q: A small insect is placed 7.65 cm from a 8.00 cm -focal-length lens. Part A Calculate the position of…
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Q: -. Two convex lenses are arranged one after the other (lens 1 on your left and lens 2 on the right).…
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Q: ** 30. A pebble 1 cm tall is placed 40 cm to the left of a +5-diopter lens. A -5-diopter lens is…
A: Given that **30. A pebble 1 cm tall is placed 40 cm to the left of a +5-diopter lens. A -5-diopter…
Q: An object with a height of 2.55 cm is placed 36.2 mm to the left of a lens with a focal length of…
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Q: - 25 cm. An object of height 2.8 cm is placed at 28 cm in front of a diverging lens of focal length,…
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Q: ou go for a free eye test in City Pharmacy. (a) The prescription given to you for eyeglasses reads:…
A: Given- power P = +2.0 D
Q: Question 4: The image of an object located at 20 cm in front of the lens is formed at 40cm behind…
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Q: Two converging lenses having focal lengths of f₁ = 11.9 cm and f₂ = 20.0 cm are placed d₁ = 53.5 cm…
A: Imagine if, in the absence of a second lens, light rays from an object would travel through the…
Q: Can you please explain how...well...how this works. Can you draw a diagram or something? It…
A: what do v and u stand for? I know they're distances, but what words do the letters represent?…
Q: Two 25.0-cm-focal-length converging lenses are placed 50.0 cm apart. An object is placed 30.0 cm in…
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Q: 6. A convex (converging) lens has a focal length of 12.5 cm. Where on the lens axis should an object…
A: Focal length = f=12.5 cm = 0.125 m magnification(virtual image) = 2.50 (1/i)+(1/u)=1/f
Q: In the following three scenarios, an object is located on one side of a converging lens. In each…
A: Given Data Focal length = 60 cm object distance p = 60cm, 7.06 cm, 300 cm. Lens Formula 1f=1p+1q
Q: Determine which df th fo llowing" equations. can be eigen function equation +and qive tk values an…
A: Since we know Eigen value should satisfy , A^x=ax a. dsinπx2dx= π2cos x=Not eigen function…
Q: 7. What are the image height and orientation produced by the setup in the following figure? Object…
A: Given data: Object distance from the lens is, u= 10 cm Object height is, h= 5 cm Focal length is, f=…
Q: Two thin lenses with focal lengths of magnitude 15.0 cm, the first diverging and the second…
A: The given information is: Two thin lenses with focal lengths of magnitude 15.0 cm, the first…
Q: 6. An object is place lens. Its image forms the lens? * O 19 cm O 9.6 cm O 2.7 cm O 6.1 cm
A: Lens is convex lens is positive The formula of obtaining the focal length of convex lens is given by…
Q: The diagram shows 2 out of the 3 possible principal rays traversing a thin lens of unknown type. The…
A:
Q: Which of the following statements is true about an eye that is farsighted? Question 17 options:…
A: Explanation: Farsightedness, also known as hyperopia, is a common refractive error of the eye where…
![[40] Your friend, Velma, has lost her glasses and is having difficulty seeing because of her
hyperopia (farsightedness). Discuss whether there is any way a magnifying glass (convex lens)
with an 8.5 cm focal length will help her to see. Include ray diagrams to illustrate whether the
magnifying glass helps or not. You may include sample calculations as evidence of your
conclusions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f81ff00-4de3-4481-8d74-7de835c54d92%2Ff3ba4be8-7eb4-4680-87ac-48a4730f90ac%2F0tx9bpt_processed.png&w=3840&q=75)
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- The figure shows an object and its image formed by a thin lens. Assume that d1 = 0.595 m, d2 = 0.784 m, and h = 7.50E-2 m. What is the image height (in m; answer sign and magnitude)?A small insect is placed 5.40 cmcm from a 6.00-cmcm-focal-length lens. a) Calculate the position of the image. Follow the sign conventions. Express your answer using two significant figures and include the appropriate units. b) Calculate the angular magnification. Express your answer using two significant figures.5. Consider a converging lens that has a focal length (f). Which one of these is correct about the image when the object is placed in front of the lens at a distance of (3f)? The image is real, inverted, and diminished The image is real, erect, and diminished The image is real, erect, and magnified The image is virtual, inverted, and magnified The image is virtual, inverted, and diminished The image is virtual, erect, and has the same size as the object A nearsighted man uses his ideally prescribed eyeglasses that have a refractive power of -3.00 diopters. He would like a prescription for contact lenses. What is the correct contact lens prescription if he normally wears his eyeglasses a distance of 2.1 cm from his eyes? diopters
- A person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smaller= 3. A 15 cm tall object sits 80 cm to the left of a converging lens with a focal length of fi 30 cm. There is a second converging lens with a focal length of f2 = 20 cm sitting 60 cm to the right of the first converging lens. dige de a. Where is the image from the first lens formed? (find di1) f₁ = 30 cm do = 80cm di = ? C. -14 1-do₂ 'वे di = [130 - 50 ] = 48 cm to the right of lens 1 = b. What is the object distance for the second lens? (find doz) f₂ =20 cm do=48 cm di = ? Where is the final image formed? (find diz) do d. What is the distance between the original object and the final image? What is the overall magnification for this two-lens system? f. What is the height of the final image? (find hi2) 2Hi there I need the solution for d). You guys are great!!!!!!!An object is placed at a distance of 1.33 metres from a convex lens that has a focal length of 40 millimetres.d) If the object’s distance from the lens was shortened to 1.33 centimetres, how would the focused image change, including the magnification?
- I continue to get the wrong answer. TIA.A person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smaller11: Use ray tracing (or any other correct method) to find the image of the arrow formed by the thin converging lens. One focal point is shown, 20 cm to the left of the lens. (1 square is 2 cm wide.) The arrow is 7.5 cm to the left of the lens. f
- A small object is placed to the left of a convex lens and on its optical axis. The object is 46 cm from the lens, which has a focal length of 15 cm.Determine the location of the image formed by the lens. (Enter your answer in cm from the lens.) 1. cm from the lens 2. Describe the image.A converging lens has a focal length of 29 cm. An object is placed 10.2 cm in front of the lens. What is the location of the image? cm b. What is the magnification? c. Is the image upright, or inverted? ONLY 1 ATTEMPT IS ALLOWED FOR THIS PART. --Select-v d. Is the image in front of the lens, or behind the lens? ONLY 1 ATTEMPT IS ALLOWED FOR THIS PART. --Select-- v