Answered: 40 kN 150° 12 300 kN FNה ר | bartleby

Related questions

Question

Compute the magnitude and direction of the resultant of the three forces shown in the
figure and locate its intersection with x and y axes. Each square is 1m on sides.

i50°
340 kN
12
300 kN
722 kN

Expert Solution

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

4. The exit of a freeway has been designed so that a car can travel safely around the curved section of the ramp when the road is wet. The banking angle enables a car to travel around the curved section without relying on friction, as shown in the diagram below: 0 (a) On the diagram above, draw and label vectors to show the normal force and gravitational force acting on the car.
A 150 Newton force is pulling 70 degrees above the horizontal and somewhat to the right. Tell me first the vertical and second the horizontal magnitudes in Newtons of the two smaller vectors that could be added to get this larger vector.
A skier is standing on a 30o hill. Draw the hill and add idealized force vectors that represent the force of the skier (FS), the normal force (FN), and the force of friction (FF).
Our vectors P and Q have the same amount. How can we rearrange them so that the sum of them is toward the right? Explain this?
ANY HELP WOULD BE APPRECIATED, THANKS
If an object is on an inclined plane having an angle e, what is the component of weight (w) parallel to incline?
What is the relation between A×B and BxA, The magnitudes are the same but they are in opposite directions, i.e., (Ã×B)=-(BxÃ) The order of the vectors in a cross product doesn't matter so they are the same, i.e., (ÃxB)=(BxÃ)