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40 + 70j + j100 tan 0.67 = 100 100 + j(40 + 70j) tan 0.67 40–237.8j 40 + 70j + j100 × (-3.078) = 100 100 + j(40 + 70j) x (-3.078) 241.142279.55° = 100 338.634338.68° 100 x 0.714 - 5139 = 100 315.46 – 123.12j = 100 x (0.36 – 0.61j)

40 + 70j + j100 tan 0.67 = 100 100 + j(40 + 70j) tan 0.67 40–237.8j 40 + 70j + j100 × (-3.078) = 100 100 + j(40 + 70j) x (-3.078) 241.142279.55° = 100 338.634338.68° 100 x 0.714 - 5139 = 100 315.46 – 123.12j = 100 x (0.36 – 0.61j)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Explain how got complex number bit
40 + 70j + j100 tan 0.6 100 100 + j(40 + 70j) tan 0.67 40–237.8j 40 + 70j + j100 × (-3.078) = 100 100 + j(40 + 70j) x (-3.078) 241.142279.55° = 100 338.634338.68° 100 x 0.712 - 5139 = 100 315.46 – 123.12j = 100 x (0.36 – 0.61j)
Transcribed Image Text:40 + 70j + j100 tan 0.6 100 100 + j(40 + 70j) tan 0.67 40–237.8j 40 + 70j + j100 × (-3.078) = 100 100 + j(40 + 70j) x (-3.078) 241.142279.55° = 100 338.634338.68° 100 x 0.712 - 5139 = 100 315.46 – 123.12j = 100 x (0.36 – 0.61j)
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