40 6 in Rectangular Pyramid 13 in 6 in T Length = 6 Width = 6 Height = 13 Slant Height = 13.3 Cylinder 12 in 80 @ 2 in 13.3 in Q 2 V= 0 1/3 in³ > MacBook Air c K SA: DII DD in² 4

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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2
F2
W
S
Rectangular Pyramid
6 in
13 in
6 in
Length = 6
Width = 6
T
Height = 13
Slant Height = 13.3
#3
Cylinder
12 in
80
F3
E
7 @
D
X C
2 in
$
4
13.3
in
F4
R
LL
%
do L
5
V
K-
V=
뽀
F5
T
G
6
B
1/3 -
3
in ³
MacBook Air
C
F6
Y
H
&
7
F7
U
N
*
8
J
SA:
DII
F8
1
M
(
9
K
in 2
8
F9
0
L
)
0
L
7
F10
P
>
F11
[
+ 11
?
11
Transcribed Image Text:2 F2 W S Rectangular Pyramid 6 in 13 in 6 in Length = 6 Width = 6 T Height = 13 Slant Height = 13.3 #3 Cylinder 12 in 80 F3 E 7 @ D X C 2 in $ 4 13.3 in F4 R LL % do L 5 V K- V= 뽀 F5 T G 6 B 1/3 - 3 in ³ MacBook Air C F6 Y H & 7 F7 U N * 8 J SA: DII F8 1 M ( 9 K in 2 8 F9 0 L ) 0 L 7 F10 P > F11 [ + 11 ? 11
You have narrowed it down between 3 shapes for your new cereal box design: a
rectangular prism, a rectangular pyramid, and a cylinder. Find the volume and surface
area for each. Show all work in the given box. Round answers to the nearest tenth.
0
F2
N
S
Cereal Box Design Volume Surface Area
Rectangular Prism
2 in.
#3
Rectangular Pyramid
7 in.
80
F3
E
D
$
11 in.
4
♂
Q
F4
R
F
LL
8
S
1
8
8
9
E
3
8
B
1
1
1
do L
%
5
1
$
3
V=
1
F5
T
G
1
6
in³
F6
Y
&
7
F7
U
1
B
8
B
*
1
2
B
8
1
8
8
5
S
1
S
B
E
A
8
1
SA:
DII
F8
8
B
9
HJK
1
in²
2
F9
0
0
L
7
F10
3
I
}
S
P
}
$
2
B
E
2
P
Transcribed Image Text:You have narrowed it down between 3 shapes for your new cereal box design: a rectangular prism, a rectangular pyramid, and a cylinder. Find the volume and surface area for each. Show all work in the given box. Round answers to the nearest tenth. 0 F2 N S Cereal Box Design Volume Surface Area Rectangular Prism 2 in. #3 Rectangular Pyramid 7 in. 80 F3 E D $ 11 in. 4 ♂ Q F4 R F LL 8 S 1 8 8 9 E 3 8 B 1 1 1 do L % 5 1 $ 3 V= 1 F5 T G 1 6 in³ F6 Y & 7 F7 U 1 B 8 B * 1 2 B 8 1 8 8 5 S 1 S B E A 8 1 SA: DII F8 8 B 9 HJK 1 in² 2 F9 0 0 L 7 F10 3 I } S P } $ 2 B E 2 P
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