40 .970 21 50 hat 2 people among 23 have the same birthday is .507, a little more than surprised at this result; somehow it seems that a larger number of е are ing calculator, we can graph the probability formula in the previous nction of n, but the graphing calculator must be set to evaluate nteger points. Figure 9.11 was produced on a TI-84+ by letting r X)/365 on the interval 0 x < 47. (This domain ensures integer required. 6 39. This is because tice that the graph does not extend past x = are too large for the calculator when n 40 rt 2 6ngiras es in , the Computer Defects A shipment of 8 computers contains 3 with defects. Find the probability that a sample of the given size, drawn from the 8, will not contain a defective computer. (See Example 3.) 3. 1 4. 2 e). 5. 3 6. 5
40 .970 21 50 hat 2 people among 23 have the same birthday is .507, a little more than surprised at this result; somehow it seems that a larger number of е are ing calculator, we can graph the probability formula in the previous nction of n, but the graphing calculator must be set to evaluate nteger points. Figure 9.11 was produced on a TI-84+ by letting r X)/365 on the interval 0 x < 47. (This domain ensures integer required. 6 39. This is because tice that the graph does not extend past x = are too large for the calculator when n 40 rt 2 6ngiras es in , the Computer Defects A shipment of 8 computers contains 3 with defects. Find the probability that a sample of the given size, drawn from the 8, will not contain a defective computer. (See Example 3.) 3. 1 4. 2 e). 5. 3 6. 5
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Can u please do number 3.
![40
.970
21
50
hat 2 people among 23 have the same birthday is .507, a little more than
surprised at this result; somehow it seems that a larger number of
е are
ing calculator, we can graph the probability formula in the previous
nction of n, but the graphing calculator must be set to evaluate
nteger points. Figure 9.11 was produced on a TI-84+ by letting
r X)/365 on the interval 0 x < 47. (This domain ensures integer
required.
6
39. This is because
tice that the graph does not extend past x =
are too large for the calculator when n 40
rt 2
6ngiras
es in
, the
Computer Defects A shipment of 8 computers contains 3 with
defects. Find the probability that a sample of the given size, drawn from
the 8, will not contain a defective computer. (See Example 3.)
3. 1
4. 2
e).
5. 3
6. 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F236cbe9f-8378-4072-848f-6d296914f439%2F19f16b15-df6d-4ef5-9697-964d5004bbd6%2Fyrzufio.jpeg&w=3840&q=75)
Transcribed Image Text:40
.970
21
50
hat 2 people among 23 have the same birthday is .507, a little more than
surprised at this result; somehow it seems that a larger number of
е are
ing calculator, we can graph the probability formula in the previous
nction of n, but the graphing calculator must be set to evaluate
nteger points. Figure 9.11 was produced on a TI-84+ by letting
r X)/365 on the interval 0 x < 47. (This domain ensures integer
required.
6
39. This is because
tice that the graph does not extend past x =
are too large for the calculator when n 40
rt 2
6ngiras
es in
, the
Computer Defects A shipment of 8 computers contains 3 with
defects. Find the probability that a sample of the given size, drawn from
the 8, will not contain a defective computer. (See Example 3.)
3. 1
4. 2
e).
5. 3
6. 5
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