4.95 mol of N2 at 20.5 °C and 6.10 bar undergoes a transformation to the state described by 395 °C and 2.95 bar. Part A Calculate AS if CP.m = 30.81 – 11.87 x 10-3 + 2.3968 × 10-5 T K? 1.0176 × 10-8 T³ J/(mol-K)
4.95 mol of N2 at 20.5 °C and 6.10 bar undergoes a transformation to the state described by 395 °C and 2.95 bar. Part A Calculate AS if CP.m = 30.81 – 11.87 x 10-3 + 2.3968 × 10-5 T K? 1.0176 × 10-8 T³ J/(mol-K)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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4.95 mol of N2 at 20.5 ∘C and 6.10 bar undergoes a transformation to the state described by 395 ∘C and 2.95 bar .
Calculate ΔS
![I Review | Constants I Periodic Table
4.95 mol of N2 at 20.5 ° C and 6.10 bar undergoes a transformation to the state described by 395 °C and 2.95 bar .
Part A
Calculate AS if
CP,m
= 30.81 – 11.87 × 10-3 + 2.3968 × 10-5 T²
K
1.0176 × 10-8 T³
K3
J/(mol-K)
K?
Express your answer with the appropriate units.
HÅ
J
AS = | 120.2
K
Submit
Previous Answers Request Answer
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Transcribed Image Text:I Review | Constants I Periodic Table
4.95 mol of N2 at 20.5 ° C and 6.10 bar undergoes a transformation to the state described by 395 °C and 2.95 bar .
Part A
Calculate AS if
CP,m
= 30.81 – 11.87 × 10-3 + 2.3968 × 10-5 T²
K
1.0176 × 10-8 T³
K3
J/(mol-K)
K?
Express your answer with the appropriate units.
HÅ
J
AS = | 120.2
K
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 5 attempts remaining
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