As per your 3-part questions policy, please only answer part d within the image provided. Thank you very much. 4.67. Methane and oxygen react in the presence of a catalyst to form formaldehyde. In a parallel reaction,methane is oxidized to carbon dioxide and water:CH4 + O₂ → HCHO + H₂OCH4 +202 → CO₂ + 2H₂OThe feed to the reactor contains equimolar amounts of methane and oxygen. Assume a basis of 100 molfeed/s.(a) Draw and label a flowchart. Use a degree-of-freedom analysis based on extents of reaction todetermine how many process variable values must be specified for the remaining variable values tobe calculated.(b) Use Equation 4.6-7 to derive expressions for the product stream component flow rates in terms ofthe two extents of reaction, ₁ and ₂.The fractional conversion of methane is 0.900 and the fractional yield of formaldehyde is 0.855.Calculate the molar composition of the reactor output stream and the selectivity of formaldehydeproduction relative to carbon dioxide production.(d) A classmate of yours makes the following observation: "If you add the stoichiometric equations forthe two reactions, you get the balanced equation2CH4 +302 HCHO + CO₂ + 3H₂OThe reactor output must therefore contain one mole of CO₂ for every mole of HCHO, so theselectivity of formaldehyde to carbon dioxide must be 1.0. Doing it the way the book said to do it, Igot a different selectivity. Which way is right, and why is the other way wrong?" What is yourresponse?

A mixture of methane and oxygen in equimolar amount is fed to the reactor.A process flow diagram is shown below:Degree of freedom analysis:Number of unknowns = 5 (n1, n2, n3, n4, and n5)Number of independent equations = 3 (C, H, and O atomic balance)Therefore,DOF = 5-3DOF = 2It means two more variables must be specified to completely define the process.The flow rate of each species in the product can be in expressed in terms of extent of reaction as followsFractional conversion of methane = 0.9Fractional yield of formaldehyde = 0.855The molar flow rate of methane in the product stream becomes,Molar flow rate of HCHO formed is calculated as follows:Total methane reacted = 45 mol/s (50-5)Methane reacted from first reaction = 42.75 mol/sThus,Methane that would react from side reaction = 2.25 mol/sFrom the stoichiometry of reaction, CO2 formed = 2.25 mol/sTherefore, the extent of reaction 1 and 2 becomes,Flow rates of water, oxygen in the reactor effluent becomes,Selectivity of formaldehyde relative to carbon dioxide is calculated as follows:Response to your classmate:Your classmate's observation is partially correct. If you add the stoichiometric equations for the two reactions, you indeed get:2CH4 + 3O2 → HCHO + CO2 + 3H2OHowever, this equation represents the overall balanced equation for the combined reaction of both pathways, not the selectivity for a specific reaction. To calculate selectivity, you need to consider the fractional yield of formaldehyde (HCHO) and the fractional yield of carbon dioxide (CO2) for each reaction pathway, as shown in part (c).All parts are solved in the above steps