4.54 WP An air-conditioning system is shown in Fig. P4.54 in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of 50 m³/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy ef- fects, determine at steady state a. the mass flow rate of the refrigerant, in kg/min. b. the rate of heat transfer, in kJ/min, between the air and refrigerant.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
4.54 WP An air-conditioning system is shown in Fig. P4.54 in
which air flows over tubes carrying Refrigerant 134a. Air enters with
a volumetric flow rate of 50 m³/min at 32°C, 1 bar, and exits at 22°C,
0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20%
and exits at 5 bar, 20°C. Ignoring heat transfer at the outer surface of
the air conditioner, and neglecting kinetic and potential energy ef-
fects, determine at steady state
a. the mass flow rate of the refrigerant, in kg/min.
b. the rate of heat transfer, in kJ/min, between the air and refrigerant.
3
+
R-134a
P3 = 5 bar
x3 = 0.20
Refrigerant 134a
Air
P₁ = 1 bar
T₁= 32°C = 305 K
(AV)₁ = 50 m³/min
Air
2+P₂=0.95 bar
T₂ = 22°C = 295 K
R-134a
P4 = 5 bar
T4 = 20°C
Transcribed Image Text:4.54 WP An air-conditioning system is shown in Fig. P4.54 in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of 50 m³/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy ef- fects, determine at steady state a. the mass flow rate of the refrigerant, in kg/min. b. the rate of heat transfer, in kJ/min, between the air and refrigerant. 3 + R-134a P3 = 5 bar x3 = 0.20 Refrigerant 134a Air P₁ = 1 bar T₁= 32°C = 305 K (AV)₁ = 50 m³/min Air 2+P₂=0.95 bar T₂ = 22°C = 295 K R-134a P4 = 5 bar T4 = 20°C
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Knowledge Booster
Refrigeration and Air Conditioning
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY