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4.49 Use the mesh-current method to find the total power dissipated in the circuit 18 V + 3 Ω w ΖΩ 9Ω Φ 4) 3 A Answer p187 = 10.8W,p3Ω = 34.56W Total dissioated power paiss = 99W 6Ω 1.08W,pzΩ = 0.72W, p9Ω = - 51.84W, ΡσΩ = 15 V

4.49 Use the mesh-current method to find the total power dissipated in the circuit 18 V + 3 Ω w ΖΩ 9Ω Φ 4) 3 A Answer p187 = 10.8W,p3Ω = 34.56W Total dissioated power paiss = 99W 6Ω 1.08W,pzΩ = 0.72W, p9Ω = - 51.84W, ΡσΩ = 15 V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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4.49 Use the mesh-current method to find the total power dissipated in the circuit 18 V + 3Ω - 2 Ω M 10.8W,P30 Answer P18v = 34.56W Total dissioated power Paiss = 99W 92 m D 13 A 6Q + 1.08W,P2n = 0.72W, p⁹n = 51.84W, P = 15 V
Transcribed Image Text:4.49 Use the mesh-current method to find the total power dissipated in the circuit 18 V + 3Ω - 2 Ω M 10.8W,P30 Answer P18v = 34.56W Total dissioated power Paiss = 99W 92 m D 13 A 6Q + 1.08W,P2n = 0.72W, p⁹n = 51.84W, P = 15 V
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