4.3-6. An insurance company sells both homeowners insurance and automobile deductible insurance. Let X be the deductible on the homeowners' insurance and Y the deductible on automobile insurance. Among those who take both types of insurance with this company, we find the following probabilities: y 1000 500 100 100 0.05 0.10 0.20 X 500 0.10 0.20 0.10 1000 0.15 0.05 0.05 (a) Compute the following probabilities: P(X = 500), P(Y = 500), P(Y = 500|X = 500), P(Y= 1001 X= 500). (b) Compute the means x, y, and the variances a, 3. (c) Compute the conditional means E(X|Y E(Y|X= 500). 100), =
4.3-6. An insurance company sells both homeowners insurance and automobile deductible insurance. Let X be the deductible on the homeowners' insurance and Y the deductible on automobile insurance. Among those who take both types of insurance with this company, we find the following probabilities: y 1000 500 100 100 0.05 0.10 0.20 X 500 0.10 0.20 0.10 1000 0.15 0.05 0.05 (a) Compute the following probabilities: P(X = 500), P(Y = 500), P(Y = 500|X = 500), P(Y= 1001 X= 500). (b) Compute the means x, y, and the variances a, 3. (c) Compute the conditional means E(X|Y E(Y|X= 500). 100), =
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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