4.2.15. Let 7T be the observed mean of a random sample of size n from a distributionhaving mean u and known variance o2. Find n so that T - 0/4 to T+ o/4 is anapproximate 95% confidence interval for u.

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Answered: 4.2.15. Let T be the observed mean of a…

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Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Q2: Let x1,X2, . , Xn and y1, y2, ..., Ym represent two independent random samples from the respective normal distributions N(H1,07) and N (H2, 03). It is given that of = 30, but ožis unknown. Then 1. A random variable that can be used to find a 95% confidence interval for - is (x- y) - (H1 - H2) А. ns3 + ms n+m. 3(n+m-2)"tm, nm O A (x – y) – (41 – H2) В. ns? + ms; n + m. (n + m – - 2) пт (x – y) – (41 - H2) С. ns3 + mS;_n+3 3(n+ m-2) ("+3m nm Ос
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1. Six batteries taken at random from a large lot were subjected to life tests with the following results: 19, 22, 18, 16, 25, and 20 hours. Find the probability that the sample mean of x= 20 hours, as observed here, or one less than 20 hours could arise if the true mean of the lot of batteries is 21.5 hours, assuming a known variance of o = 10 hours, for the individual batteries in the lot. %3D
5.3.6 Given a normally distributed population with a mean of 100 and a standard deviation of 20, find the following probabilities based on a sample of size 16: (a) Pð"x ! 100Þ (b) Pð"x 110Þ (c)Pð96 "x 108Þ
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4.2.15. Let T be the observed mean of a random sample of size n from a distribution having mean u and known variance o2. Find n so that T - 0/4 to T+0/4 is an approximate 95% confidence interval for u.