(4.1) Determine the values of a and b, and hence write down the equation of f

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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(4.1) Determine the values of a and b, and hence write down the equation of f
(4.2) Find the values of p and r, and hence write down the equation of g.
(4.3) Write down the set D, (the domain of the function 9). Then, use the graphs (not the algebraic
expressions for f (x) and g (x)) to solve the inequality g (x) < f (x).
(4.4) Determine the equation of the inverse function g-l.
[If you were not able to find the values of p and r in 4.2, you may answer the question in terms of p
and r.)
(4.5) Show that (9-1 og) (z) = x. Include all the stepe of your reasoning.
Transcribed Image Text:(4.1) Determine the values of a and b, and hence write down the equation of f (4.2) Find the values of p and r, and hence write down the equation of g. (4.3) Write down the set D, (the domain of the function 9). Then, use the graphs (not the algebraic expressions for f (x) and g (x)) to solve the inequality g (x) < f (x). (4.4) Determine the equation of the inverse function g-l. [If you were not able to find the values of p and r in 4.2, you may answer the question in terms of p and r.) (4.5) Show that (9-1 og) (z) = x. Include all the stepe of your reasoning.
y =f(x)
y =g(x)
3
The sketch shows the graphs of the functions f and g. The function f is defined by
f (x) = a |x – 6| + 2
and the function g 1s defined by
9 (x) = log, (x – r)
where p> 0, p+1
S is the salient point of the graph of f, and the graph of g passes through the orgin and S.
Transcribed Image Text:y =f(x) y =g(x) 3 The sketch shows the graphs of the functions f and g. The function f is defined by f (x) = a |x – 6| + 2 and the function g 1s defined by 9 (x) = log, (x – r) where p> 0, p+1 S is the salient point of the graph of f, and the graph of g passes through the orgin and S.
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