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4.1-1. Insulation in a Cold Room. Calculate the heat loss per m? of surface area for a temporary insulating wall of a food cold storage room where the outside temperature is 299.9 K and the inside temperature 276.5 K. The wall is composed of 25.4 mm of corkboard having a k of 0.0433 W/m - K.

4.1-1. Insulation in a Cold Room. Calculate the heat loss per m? of surface area for a temporary insulating wall of a food cold storage room where the outside temperature is 299.9 K and the inside temperature 276.5 K. The wall is composed of 25.4 mm of corkboard having a k of 0.0433 W/m - K.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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4.1-1. Insulation in a Cold Room. Calculate the heat loss per m? of surface area for a temporary insulating wall of a food cold storage room where the outside temperature is 299.9 K and the inside temperature 276.5 K. The wall is composed of 25.4 mm of corkboard having ak of 0.0433 W/m - K. 4,2-2. Heat Removal of a Cooling Coil. A cooling coil of 1.0 ft of 304 stainless-steel tubing having an inside diameter of 0.25 in. and an outside diameter of 0.40 in. is being used to remove heat from a bath. The temperature at the inside surface of the tube is 40°F and is 80*F on the outside. The thermal conductivity of 304 stainless steel is a function of temperature: k = 7.75 + 7.78 x 10-T where k is in btu/h ft "F and T is in "F. Calculate the heat removal in btu/s and watts.
Transcribed Image Text:4.1-1. Insulation in a Cold Room. Calculate the heat loss per m? of surface area for a temporary insulating wall of a food cold storage room where the outside temperature is 299.9 K and the inside temperature 276.5 K. The wall is composed of 25.4 mm of corkboard having ak of 0.0433 W/m - K. 4,2-2. Heat Removal of a Cooling Coil. A cooling coil of 1.0 ft of 304 stainless-steel tubing having an inside diameter of 0.25 in. and an outside diameter of 0.40 in. is being used to remove heat from a bath. The temperature at the inside surface of the tube is 40°F and is 80*F on the outside. The thermal conductivity of 304 stainless steel is a function of temperature: k = 7.75 + 7.78 x 10-T where k is in btu/h ft "F and T is in "F. Calculate the heat removal in btu/s and watts.
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