4. Зx2 + — 8(у + 1) %3D 0 x3 dy y+1

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A: The solution are next step

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A: The given differential equation is,let us substitute t=ez so z=logt and hence

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Q: y = Cje² + C2xe* + C3x²e* %D O y" + 3y" + 3y' + y = 0 y" – 3y" + 3y' + y = 0 %3D + 3y" + 3y' – y = 0…

A: Given data is: y=C1ex+C2xex+C3x2ex

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A: