4. You can easily find the time constant if you are given a graph of voltage across a discharging capacitor as a function of time. When t = Tc = RC, the voltage across the capacitor is AVc(t = Tc) = AV, e¹≈ 0.37 AV Therefore the time constant is just how long it takes for AVC(t) to reach 37% of its initial value. The graph shows the voltage across a discharging 0.2 μF capacitor as a function of time. Use the following steps to determine the resistance. a. What is 37% of the initial voltage? 21 b. How long does it take (after discharge starts) for the voltage to reach 37% of the initial voltage? This time is equal to the time constant. c. Use your time constant from (b) to determine the resistance. AV (Volts) 2 1.5 1 0.5 %40 80 120 160 time (milli-sec)

4. You can easily find the time constant if you are given a graph of voltage across a discharging capacitor as a function of time. When t = Tc = RC, the voltage across the capacitor is AVc(t = Tc) = AV, e¹≈ 0.37 AV Therefore the time constant is just how long it takes for AVC(t) to reach 37% of its initial value. The graph shows the voltage across a discharging 0.2 μF capacitor as a function of time. Use the following steps to determine the resistance. a. What is 37% of the initial voltage? 21 b. How long does it take (after discharge starts) for the voltage to reach 37% of the initial voltage? This time is equal to the time constant. c. Use your time constant from (b) to determine the resistance. AV (Volts) 2 1.5 1 0.5 %40 80 120 160 time (milli-sec)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Four capacitors are arranged in the circuit shown in the figure. The values of the capacitors are C1…

Q: Capacitors C₁ = 5.0 μF and C₂ = 2.0 μF are charged as a parallel combination across a 170 V battery.…

Q: Capacitor C has a potential energy, PE.. If the charge on capacitor C increases by a factor of 7,…

Q: Consider three capacitors with capacitances C1 = 10 μF. C2 = 20 μF, and C3= 30 µF connected in…

A: Given, C1 = 10 microfarad C2 = 20 microfarad C3 = 30 microfarad Voltage source of = 100V We need to…

Q: Your Answer: 100.0 V Answer 15.0μF 20.0 25.010.0μF μF 25.0ΩΣ x10 ww 15.00 In the circuit in the…

Q: The circuit in the figure below contains a 9.00 V battery and four capacitors. The two capacitors on…

Q: + C1 C2

Q: RC Circuit - Discharging You have an RC Circuit - a Resistor and Capacitor (in series). The system…

A: Given data: The resistance value is, R= 29 kΩ The capacitance value is, C= 40 μF The capacitor…

Q: The capacitance of the four capacitors shown in the circuit diagram are given in terms of C. C B 2C…

Q: 57°F Sunny Exam in Progress Two capacitors (C₁ = 4.0 µF and C₂ = 7.0 µF) are connected in series. If…

Q: A) Choose true or false for each statement regarding a parallel plate capacitor.. The charge of…

Q: = 3880 2. What are the potential In the figure ɛ = 9.46 V, R1 = 2630 N, R2 differences (in V) (a) VA…

A: Let I denote the current through the whole circuit. Let I1 is the current through the resistor R1 of…

Q: A circuit includes an array of capacitors arranged as follows. Two 5pF capacitors are in parallel…

A: Given: Let capacitor C1 = C2 = 5 pF be in parallel. Let C3 = 5 pF , C4 = 10 pF , C5 = 15 pF ,…

Q: A 15-μF capacitor and a 30-μF capacitor are connected in series, and charged to a potential…

Q: In the figure R₁ = 5.03 02, R₂ = 10.11 02, R3 = 15.04, C₁ = 5.19 µF, C₂ = 10.25 µF, and the ideal…

Q: Several identical capacitors are connected in series to obtain a total value ofCs, then they are all…

A: Given:Let the number of capacitors be n and c be the capacitance of each of them.When they are…

Q: In the circuit shown, all capacitors are charged. The charge on the capacitor C2 is Q2= 20 µC. What…

Q: Four capacitors are connected as shown in the figure below. (C = 16.0 μF.) C 3.00 με a Hh. 6.00 με…

Q: In the circuit shown in the figure the voltage of the battery is 16.0 V, and the capacitors have the…

A: Given Data: The value of the supplied voltage is The value of the capacitors is 2.96 mF, 2.83 mF,…

Q: A combination of series and parallel connections of capacitors is shown in the figure. The sizes of…

Q: apacitors have capacitances (a) in parallel (b) in series HF μF ut pt. equivalent capacitance they…

Q: Three capacitors are arranged in a circuit as in the figure Vo = battery voltage = 12.0 V C2…

Q: Two Capacitors are in series. C1=304 μF and C2=295 μF. What is the equivalent capacitance of the…

A: The equivalent capacitance of the capacitors series combination is, C=C1C2C1+C2

Q: A 14.5-μF capacitor is charged to a potential of 40.0 V and then discharged through a 65.0 Ω…

A: Given C=14.5μF V=40V R=65 Ω

Q: Can you explain how the voltage drop across capacitor C2 is equal to 2V?

Q: Consider three capacitors with capacitances C1 = 10 µF, C2 = 20 µF, and C3 = 30 µF connected in…

Q: 5. A 12.0 V battery and 3 uncharged capacitors capacitances C1 = 4.00 µF, C2 = of Vo C3 6.00 µF, and…

Q: The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 360 V…

Q: What is the time constant for the discharge of the capacitors in the figure? Express your answer in…

A: Given What is the time constant for the discharge of the capacitors in the figure? Express your…

Q: Problem 3: Two capacitors are in a circuit, connected in parallel as shown in the figure. The…

A: Part (a) Equivalent capacitance, Part (b) C= 5.2μF+11.4μF=16.6μF

Q: Consider the circuit shown in the figure below. The four capacitors have capacitances C1=17uF,…

A: Voltage across C4 is 14.85 Volts

Q: Problem 1: Two capacitors are connected in a circuit in series as shown in the figure. The…

Q: The circuit in the figure below has been connected for a long time. Let R₁ = 7.800 and R₂ = 5.80 0.…

A: R1=7.80 ohmR2=5.80 ohmIn the circuit, over what time interval does the capacitor discharge to…

Concept explainers

Combination of Capacitors

The connection of capacitors can be established in a circuit in two ways.

Question

4. You can easily find the time constant if you are given a graph of voltage across a discharging capacitor as a function
of time. When t = Tc = RC, the voltage across the capacitor is
AV (t = Tc) = AV, e¹≈ 0.37 AV
Therefore the time constant is just how long it takes for AV (t) to reach 37% of its initial value.
The graph shows the voltage across a discharging 0.2 μF capacitor as a function of time. Use the following steps to
determine the resistance.
a. What is 37% of the initial voltage?
21
b. How long does it take (after discharge starts) for the voltage to reach
37% of the initial voltage? This time is equal to the time constant.
c. Use your time constant from (b) to determine the resistance.
AV (Volts)
2
1.5
0.5
%40 80 120 160
time (milli-sec)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Determine the given variables

VIEW

Step 2: Calculate voltage across capacitor

VIEW

Step 3: Calculate time

VIEW

Step 4: Calculate resistance R

VIEW

Solution

VIEW

Step by step

Solved in 5 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Item 15 Now we will consider some slightly different related scenarios to Example 21-18. Part A Example 21-18 depicts the following scenario. A circuit consists of a resistor R₁ = 126-, a resistor R₂ = 275-, a capacitor C = 182-μF, a switch, and an € = 3.00-V battery all connected in series. Initially the capacitor is uncharged and the switch is open. At time t=0 the switch is closed. increase decrease stay the same 3.00 V Suppose the resistance of the 126-2 resistor is reduced by a factor of 2. Assume everything else in the problem remains the same. Does the final value of the charge on the capacitor increase, decrease, or stay the same? Submit Request Answer ww 126 Ω 182 μF HH 275 Ω < 15 of 15 Review
EMF = Vo = 6 volts. and C = 5 μF Calculate the theoretical value of the charge (q) in the capacitor during charging at t = RC. Use equation 3.
A dielectric-filled parallel-plate capacitor has plate area A = 10.0 cm2cm2 , plate separation d = 5.00 mmmm and dielectric constant k = 4.00. The capacitor is connected to a battery that creates a constant voltage V = 15.0 VV . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2C2/N⋅m2 . The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the capacitor is half-filled with the dielectric. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3. In the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work is done by the external agent acting on the dielectric?
A leaky capacitor loses 22% of its charge in 13 min. What is the effective time constant of the system? The time constant, t = What fraction of charge (in %) will be on the capacitor after 39 min? Q Qo After what time there will be 4% of the initial charge left on the capacitor? The charge, The time, t = Units Select an answer ✓ x 100% = Units Select an answer ✓ Units Select an answer ✓
11:31 PM Sat Jul 15 = Consider the combination of capacitors in the figure below. (Let C₁ = 36.0 µF and C₂ + FL-I 36.0 V 4.00 μF C₂ webassign.net (a) Find the equivalent single capacitance of the two capacitors in series. UF Redraw the diagram (called diagram 1) with this equivalent capacitance. 8.00 με (b) In diagram 1 find the equivalent capacitance of the three capacitors in parallel. μF Redraw the diagram as a single battery and single capacitor in a loop. (c) Compute the charge on the single equivalent capacitor. UC (d) Returning to diagram 1, compute the charge on each individual capacitor. 4.00-μF capacitor 4.40-μF capacitor 36.0-μF and 8.00-μF equivalent capacitor No Does the sum agree with the value found in part (c)? Yes Need Help? Read It Submit Answer μC μC (e) What is the charge on the 36.0-μF capacitor and on the 8.00-μF capacitor? μC HC (f) Compute the voltage drop across the 36.0-μF capacitor. (g) Compute the voltage drop across the 8.00-μF capacitor. 4.40 μF.) 17%
In the figure ε = 15.6 V, R₁ = 2800 2, R2 = 2900 2, and R3 = 4070 2. What are the potential differences (in V) (a) VA - VB, (b) VB - VC, (c) Vc VD, and (d) VA - VC? Rg www R3 D
A leaky capacitor loses 5% of its charge in 5 min. What is the effective time constant of the system? The time constant, τ = Units . What fraction of charge (in %) will be on the capacitor after 10 min? The charge, QQ0×100%QQ0×100% = Units . After what time there will be 4% of the initial charge left on the capacitor? The time, t = Units .