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Control structures
Control structures are block of statements that analyze the value of variables and determine the flow of execution based on those values. When a program is running, the CPU executes the code line by line. After sometime, the program reaches the point where it has to make a decision on whether it has to go to another part of the code or repeat execution of certain part of the code. These results affect the flow of the program's code and these are called control structures.
Switch Statement
The switch statement is a key feature that is used by the programmers a lot in the world of programming and coding, as well as in information technology in general. The switch statement is a selection control mechanism that allows the variable value to change the order of the individual statements in the software execution via search.
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- int input; cout << "enter input " << endl; cin >> input; int i = input / 2; int d; for (i >= 2; i--;) { d = input % i; if (d == 2 || i == 1) cout << "not prime" << endl; else cout << "prime" << endl; } This code outputs prime numbers as both "prime" and "not prime" but I just want it to say "prime". Please help me with this problem using c++.#include <iostream> using namespace std; double calcAverage(int a, int b) { double result = 0.0; result = (a + b) / 2.0; return result; } // calcAverage int main() { int x = 100; int y = 200; double z = calcAverage(x, y); cout << z << endl; } // main Above is the partial written program that needs to be modified.using namespace std; int main() int ij.n fact,sign -1; float x, p.sum=0; cout>x; cout>n; for(i=1;i sign-1'sign; sum sign"p/fact } O exp(x) cos(x) cout using namespace std; return 0; O 4567 O 12 13 14 15 ... 14 sin (x)=x-+--+Σ0 cos (x)=1-+-+-+- exp (x) = + + + +· In(x) = Ext Σ (x-1) ixx¹ int main() { int matrix [4] [4] = {{1, 2, 3, 4), (4, 5, 6, 7), (8, 9, 10, 11), (12, 13, 14, 15}}; for (int i = 0; i < 4; i++) cout << matrix[1][i] << " "; + ۹:۱۳ ↑ 21-0 G (2/+1)! ~(-1)' xx² Li-0 (27) ↑Q1// find o/p of the program? #include main () { Int x,y,Z; X=4; Y=5; Z= x++ * y; Cout<<"x="<Compute: z = √x Y Ex: If the input is 4.0 3.0, then the output is: 1.0 #include #include #include using namespace std; int main() { double x; double y; double z; } cin >> X; cin >> y; /* Your code goes here */ cout << fixed <<<What’s the output1.Modify the code to sum even integer from 2 through 10. #include <iostream> using std::cout; using std::endl; // complete the code below cout << "Sum is " << sum << endl; // output sum return 0; // successful termination } // end function main i need it ASAP please i will appreciate itQ3:- a)find the output (explain how) #include<iostream> int f(int &x, int c) { c = c - 1; if (c == 0) return 1; x = x + 1; return f(x, c) * x; } int main() { int p = 7; cout<< f(p, p); } b) Find the output or error. #include<iostream> using namespace std; int N = 11; int main() { static int x = 1; if (cout << x << " " && x++ < N && main()) { } return 0; }#include<stdio.h> #include<conio.h> int mutex=1,full=0,empty=1,x=0; main() { int n; void producer(); void consumer(); int wait(int); int(signal); printf("\n1. Producer \n2. Consumer \n,3. Exit \n"); while(1) { printf("\n Enter the choice:"); scanf("%d", &n); switch(n); { case-1: if((mutex==1)&&(empty!=0)) producer(); else printf("Nuffer is full"); break; case-2: if((mutex==1)&&(full!=0)) consumer(); else print("Buffer is empty"); break; case-3: exit(0); break; } } } int wait(int s) {return(--s); } int signal(int s) { return(++s); } void producer() { mutex = wait(mutex); full = signal(full); empty=wait(empty); x++; printf("\n Producer produces the item %d",x); mutex= signal(mutex); } void consume() { mutex = wait(mutex); full = wait(full); empty = signal(empty); printf("\n Consumer consumes item %d",x); x--; mutex = signal(mutex); } CONVERT THIS C LANGUAGE CODE IN BASH SCRIPT THANKYOUC++ code#include <stdio.h>#include <stdlib.h>int LineFunc(void);int main(){int a, b;printf("Enter a :");scanf("%d", &a);printf("Enter b :");scanf("%d", &b);LineFunc();printf("\n\n");system("pause"); }int LineFunc(void){int i,j;int a=1, b = 0, y; for (i = -10; i < 11; i++){for (j = 10; j > -11; j--){y = a * i + b;if (i == 0 ){printf("-");}else if (j == 0){printf("|");}else if (i == 0 && j == 0){printf("+");}else if (y == j){printf("*");}elseprintf(" ");}printf("\n");} } Could you please write the code that gives different results for each value in the chart?SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. 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