4. Why does the equation of Exercise 3 imply that d(B + E dt) = 0? nod holn on #A
4. Why does the equation of Exercise 3 imply that d(B + E dt) = 0? nod holn on #A
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![Exercises 1 through 4 provide a more careful derivation of Fara-
day's law. We assume that S is a simply connected, bounded,
twice continuously differentiable surface and E and B are contin-
uously differentiable forms.
1. Given that
В,
at
E
350
11. Е%3D те?
show that
E dt
as×[to,t1]
В.
B+
Sx{to}
Sx{tı}
2. Explain why the second equation in Exercise 1 is equivalent to
B+E dt = 0.
a(S×{to,t1])
3. Using the result in the previous exercise, prove that
d(В + Edt) 3D 0.
Sx[to,ti]
4. Why does the equation of Exercise 3 imply that
d(В + Edt) — 0?
Need help on #4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F61a9e2ec-7a57-4f14-9ef6-3ef2b58bb4ec%2Fbc29b6d2-027d-4566-bcec-f14c9b0c3f71%2F8yq4k9h_processed.png&w=3840&q=75)
Transcribed Image Text:Exercises 1 through 4 provide a more careful derivation of Fara-
day's law. We assume that S is a simply connected, bounded,
twice continuously differentiable surface and E and B are contin-
uously differentiable forms.
1. Given that
В,
at
E
350
11. Е%3D те?
show that
E dt
as×[to,t1]
В.
B+
Sx{to}
Sx{tı}
2. Explain why the second equation in Exercise 1 is equivalent to
B+E dt = 0.
a(S×{to,t1])
3. Using the result in the previous exercise, prove that
d(В + Edt) 3D 0.
Sx[to,ti]
4. Why does the equation of Exercise 3 imply that
d(В + Edt) — 0?
Need help on #4
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