**Problem:**What volume of 12.0M HCl stock solution is required to produce 200 mL of a 2.50M diluted solution of HCl?**Explanation:**To find the required volume of the stock solution, you can use the dilution formula:\[ C_1V_1 = C_2V_2 \]where:- \( C_1 \) is the concentration of the stock solution (12.0M),- \( V_1 \) is the volume of the stock solution needed,- \( C_2 \) is the concentration of the diluted solution (2.50M),- \( V_2 \) is the volume of the diluted solution (200 mL).Substitute the known values into the equation and solve for \( V_1 \):\[ 12.0M \times V_1 = 2.50M \times 200 \, \text{mL} \]

We have to find, how much volume of stock solution of 12.0 M HCl solution is required to produce 200…

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4. What volume of 12.0M HCl stock solution is required to produce 200mL of a 2.50M diluted solution of HCI?

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

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**Problem:**

What volume of 12.0M HCl stock solution is required to produce 200 mL of a 2.50M diluted solution of HCl?

**Explanation:**

To find the required volume of the stock solution, you can use the dilution formula:

\[ C_1V_1 = C_2V_2 \]

where:
- \( C_1 \) is the concentration of the stock solution (12.0M),
- \( V_1 \) is the volume of the stock solution needed,
- \( C_2 \) is the concentration of the diluted solution (2.50M),
- \( V_2 \) is the volume of the diluted solution (200 mL).

Substitute the known values into the equation and solve for \( V_1 \):

\[ 12.0M \times V_1 = 2.50M \times 200 \, \text{mL} \]

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