4. What volume of 12.0M HCl stock solution is required to produce 200mL of a 2.50M diluted solution of HCI?

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**Problem:**

What volume of 12.0M HCl stock solution is required to produce 200 mL of a 2.50M diluted solution of HCl?

**Explanation:**

To find the required volume of the stock solution, you can use the dilution formula:

\[ C_1V_1 = C_2V_2 \]

where:
- \( C_1 \) is the concentration of the stock solution (12.0M),
- \( V_1 \) is the volume of the stock solution needed,
- \( C_2 \) is the concentration of the diluted solution (2.50M),
- \( V_2 \) is the volume of the diluted solution (200 mL).

Substitute the known values into the equation and solve for \( V_1 \):

\[ 12.0M \times V_1 = 2.50M \times 200 \, \text{mL} \]
Transcribed Image Text:**Problem:** What volume of 12.0M HCl stock solution is required to produce 200 mL of a 2.50M diluted solution of HCl? **Explanation:** To find the required volume of the stock solution, you can use the dilution formula: \[ C_1V_1 = C_2V_2 \] where: - \( C_1 \) is the concentration of the stock solution (12.0M), - \( V_1 \) is the volume of the stock solution needed, - \( C_2 \) is the concentration of the diluted solution (2.50M), - \( V_2 \) is the volume of the diluted solution (200 mL). Substitute the known values into the equation and solve for \( V_1 \): \[ 12.0M \times V_1 = 2.50M \times 200 \, \text{mL} \]
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