Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![### Percent Composition by Mass: Strontium in Strontium Arsenate
**Question 4**: What is the percent strontium by mass in strontium arsenate, Sr₃(AsO₄)₂?
#### Answer Choices:
a. 48.6%
b. 13.4%
c. 27.7%
d. 18.6%
e. 41.0%
When faced with a question regarding the percent composition by mass in a compound, you need to follow these steps to find the correct answer:
1. **Determine the Molar Mass of the Compound**:
- Calculate the molar mass of each element in the compound and then sum them for the total molar mass of Sr₃(AsO₄)₂.
2. **Calculate the Mass Contribution of the Desired Element**:
- Specifically, determine the total mass of strontium within the compound.
3. **Divide and Multiply by 100**:
- Use the formula:
\[
\text{Percent by mass} = \left( \frac{\text{Total mass of the element in the compound}}{\text{Molar mass of the compound}} \right) \times 100\%
### Example Calculations:
**Step 1: Calculate Molar Mass of Sr₃(AsO₄)₂**:
- Strontium (Sr): 87.62 g/mol
- Arsenic (As): 74.92 g/mol
- Oxygen (O): 16.00 g/mol
Molar mass of Sr₃(AsO₄)₂:
\[
3(87.62\ \text{g/mol}) + 2(74.92\ \text{g/mol}) + 8(16.00\ \text{g/mol})
\]
\[
= 262.86\ \text{g/mol (Sr)} + 149.84\ \text{g/mol (As)} + 128.00\ \text{g/mol (O)}
\]
\[
= 540.70\ \text{g/mol (total molar mass of Sr₃(AsO₄)₂)}
\]
**Step 2: Mass Contribution of Strontium**:
\[
\text{Total mass of Sr} = 3 \times 87.62\](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F066bb5df-9069-4300-b122-0f92c568ce58%2F6c1a73fd-982f-478b-b412-2f2a0b10d704%2F59by6r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Percent Composition by Mass: Strontium in Strontium Arsenate
**Question 4**: What is the percent strontium by mass in strontium arsenate, Sr₃(AsO₄)₂?
#### Answer Choices:
a. 48.6%
b. 13.4%
c. 27.7%
d. 18.6%
e. 41.0%
When faced with a question regarding the percent composition by mass in a compound, you need to follow these steps to find the correct answer:
1. **Determine the Molar Mass of the Compound**:
- Calculate the molar mass of each element in the compound and then sum them for the total molar mass of Sr₃(AsO₄)₂.
2. **Calculate the Mass Contribution of the Desired Element**:
- Specifically, determine the total mass of strontium within the compound.
3. **Divide and Multiply by 100**:
- Use the formula:
\[
\text{Percent by mass} = \left( \frac{\text{Total mass of the element in the compound}}{\text{Molar mass of the compound}} \right) \times 100\%
### Example Calculations:
**Step 1: Calculate Molar Mass of Sr₃(AsO₄)₂**:
- Strontium (Sr): 87.62 g/mol
- Arsenic (As): 74.92 g/mol
- Oxygen (O): 16.00 g/mol
Molar mass of Sr₃(AsO₄)₂:
\[
3(87.62\ \text{g/mol}) + 2(74.92\ \text{g/mol}) + 8(16.00\ \text{g/mol})
\]
\[
= 262.86\ \text{g/mol (Sr)} + 149.84\ \text{g/mol (As)} + 128.00\ \text{g/mol (O)}
\]
\[
= 540.70\ \text{g/mol (total molar mass of Sr₃(AsO₄)₂)}
\]
**Step 2: Mass Contribution of Strontium**:
\[
\text{Total mass of Sr} = 3 \times 87.62\
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