4. Using what you just learned about Boolean Algebra, build a circuit in Multimedia that will satisfy the following Boolean equation: X=A•B•C Draw your circuit below: Develop a truth table for your circuit below:
4. Using what you just learned about Boolean Algebra, build a circuit in Multimedia that will satisfy the following Boolean equation: X=A•B•C Draw your circuit below: Develop a truth table for your circuit below:
Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
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![---
### Understanding Boolean Algebra and Circuit Design
**The AND gate operation can also be expressed by a Boolean Algebra equation. For the two-input AND gate you just worked with, the equation is:**
\[ X = A \cdot B \]
**4. Using what you just learned about Boolean Algebra, build a circuit in Multimedia that will satisfy the following Boolean equation:**
\[ X = A \cdot B \cdot C \]
**Draw your circuit below:**
*Here, you are expected to draw a circuit diagram that represents the Boolean equation \( X = A \cdot B \cdot C \). This would typically involve three inputs (A, B, C) going into AND gates whose output is X.*
**Develop a truth table for your circuit below:**
*In this section, you are to create a truth table that reflects all possible inputs (A, B, C) and the corresponding output (X) for the Boolean equation \( X = A \cdot B \cdot C \).*
---
### Guide to Drawing the Circuit and Developing a Truth Table
**Circuit Design:**
1. **Elements Required:**
- Three input variables: A, B, and C.
- AND gates.
2. **Steps:**
- Connect input A and B to the first AND gate.
- The output of the first AND gate will join with input C at the second AND gate.
- The final output from the second AND gate will be your X.
**Truth Table:**
A truth table for the given equation \( X = A \cdot B \cdot C \) helps in predicting the output for all possible combinations of inputs A, B, and C.
| A | B | C | X |
|---|---|---|---|
| 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 |
In this table, '0' represents a LOW state or FALSE condition, and '1' represents a HIGH state or TRUE condition.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa707ac10-329d-44ed-a2d8-7c39812650b2%2Fe40e54df-9203-4454-85ce-088728a5884e%2Fs1dudht_processed.jpeg&w=3840&q=75)
Transcribed Image Text:---
### Understanding Boolean Algebra and Circuit Design
**The AND gate operation can also be expressed by a Boolean Algebra equation. For the two-input AND gate you just worked with, the equation is:**
\[ X = A \cdot B \]
**4. Using what you just learned about Boolean Algebra, build a circuit in Multimedia that will satisfy the following Boolean equation:**
\[ X = A \cdot B \cdot C \]
**Draw your circuit below:**
*Here, you are expected to draw a circuit diagram that represents the Boolean equation \( X = A \cdot B \cdot C \). This would typically involve three inputs (A, B, C) going into AND gates whose output is X.*
**Develop a truth table for your circuit below:**
*In this section, you are to create a truth table that reflects all possible inputs (A, B, C) and the corresponding output (X) for the Boolean equation \( X = A \cdot B \cdot C \).*
---
### Guide to Drawing the Circuit and Developing a Truth Table
**Circuit Design:**
1. **Elements Required:**
- Three input variables: A, B, and C.
- AND gates.
2. **Steps:**
- Connect input A and B to the first AND gate.
- The output of the first AND gate will join with input C at the second AND gate.
- The final output from the second AND gate will be your X.
**Truth Table:**
A truth table for the given equation \( X = A \cdot B \cdot C \) helps in predicting the output for all possible combinations of inputs A, B, and C.
| A | B | C | X |
|---|---|---|---|
| 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 |
In this table, '0' represents a LOW state or FALSE condition, and '1' represents a HIGH state or TRUE condition.
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