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4. Use the following information to answer the questions below. PEP + ADP → Pyruvate + ATP (AG" = -6.62kcal/mol) R= 1.987 cal/mol K T= 24°C [PEP] = .05 M [Pyruvate] = .01M [ATP]/[ADP] = 2.5 %3D а. What is the equilibrium constant for this reaction? SHOW YOUR WORK! thanks b. What is the AG in this cell under these conditions? SHOW YOUR WORK! thanks

4. Use the following information to answer the questions below. PEP + ADP → Pyruvate + ATP (AG" = -6.62kcal/mol) R= 1.987 cal/mol K T= 24°C [PEP] = .05 M [Pyruvate] = .01M [ATP]/[ADP] = 2.5 %3D а. What is the equilibrium constant for this reaction? SHOW YOUR WORK! thanks b. What is the AG in this cell under these conditions? SHOW YOUR WORK! thanks

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4. Use the following information to answer the questions below. PEP + ADP > Pyruvate + ATP (AG" = -6.62kcal/mol) R= 1.987 cal/mol K T= 24°C [PEP] = .05 M [Pyruvate] = .01M [ATP]/[ADP] = 2.5 а. What is the equilibrium constant for this reaction? SHOW YOUR WORK! thanks b. What is the AG in this cell under these conditions? SHOW YOUR WORK! thanks
Transcribed Image Text:4. Use the following information to answer the questions below. PEP + ADP > Pyruvate + ATP (AG" = -6.62kcal/mol) R= 1.987 cal/mol K T= 24°C [PEP] = .05 M [Pyruvate] = .01M [ATP]/[ADP] = 2.5 а. What is the equilibrium constant for this reaction? SHOW YOUR WORK! thanks b. What is the AG in this cell under these conditions? SHOW YOUR WORK! thanks
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