4. Two-point charges are arranged on the x-y coordinate system as follows: Q, =+ 3.0 µC at 300 cm away from the origin and Q, =– 600. 0 nC at 520 cm away. a. What is the magnitude of electric field of Q, = 3.0 µC at point P? =- 600. 0 nC at point P? b. What is the magnitude of electric field of Q, C. Use vector component method to present the horizontal and vertical components of the fields. VERTICAL COMPONENT FIELD HORIZONTAL CCOMPONENT d. What is the total electric field? Qi = + 3.0 µC 600 cm 30° ( P 520 cm Q2 = - 600.0 nC 300 cm
4. Two-point charges are arranged on the x-y coordinate system as follows: Q, =+ 3.0 µC at 300 cm away from the origin and Q, =– 600. 0 nC at 520 cm away. a. What is the magnitude of electric field of Q, = 3.0 µC at point P? =- 600. 0 nC at point P? b. What is the magnitude of electric field of Q, C. Use vector component method to present the horizontal and vertical components of the fields. VERTICAL COMPONENT FIELD HORIZONTAL CCOMPONENT d. What is the total electric field? Qi = + 3.0 µC 600 cm 30° ( P 520 cm Q2 = - 600.0 nC 300 cm
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter22: Electricity And Magnetism
Section: Chapter Questions
Problem 49CP: Two particles, each with charge 52.0 nC, are located on the y axis at y = 25.0 cm and y = 25.0 cm....
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Question
![4. Two-point charges are arranged on the x-y coordinate system as follows: Q, =+ 3.0 µC at 300 cm away
from the origin and Q :
=- 600. 0 nC at 520 cm away.
a. What is the magnitude of electric field of Q, = 3.0 µC at point P?
=- 600. 0 nC at point P?
b. What is the magnitude of electric field of Q,
C.
Use vector component method to present the horizontal and vertical components of the fields.
VERTICAL COMPONENT
FIELD
HORIZONTAL COMPONENT
d. What is the total electric field?
Qi = + 3.0 µC
600 cm
30° (
520 cm
P
Q2 = - 600.0 nC
300 cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F46d7dfc8-3ed9-4e9a-9a84-9a9b5d111e5f%2F681b071a-fb34-40e0-aa4e-414897f7a581%2Frwpj872_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. Two-point charges are arranged on the x-y coordinate system as follows: Q, =+ 3.0 µC at 300 cm away
from the origin and Q :
=- 600. 0 nC at 520 cm away.
a. What is the magnitude of electric field of Q, = 3.0 µC at point P?
=- 600. 0 nC at point P?
b. What is the magnitude of electric field of Q,
C.
Use vector component method to present the horizontal and vertical components of the fields.
VERTICAL COMPONENT
FIELD
HORIZONTAL COMPONENT
d. What is the total electric field?
Qi = + 3.0 µC
600 cm
30° (
520 cm
P
Q2 = - 600.0 nC
300 cm
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