4. The velocity of a body moving through a resisting medium with resistance proportional to the square of the velocity can be modelled by the differential equation i) dv -0.003 v², v(0) = vo. dt By separating the variables show that the velocity is given by v(t) Vo 1 +0.003 vot On a still day a small hovercraft is moving at 6m/s when its fan suddenly fails. The motion of the hovercraft thereafter can be modelled using the differential equation above. Taking vo = 6 find the hovercraft's velocity four seconds later.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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4. The velocity of a body moving through a resisting medium with resistance proportional to the
square of the velocity can be modelled by the differential equation
dv
-0.003 v?, v(0) = vo.
dt
i)
By separating the variables show that the velocity is given by
vo
v(t):
1+ 0.003 vot '
On a still day a small hovercraft is moving at 6m/s when its fan suddenly fails. The
motion of the hovercraft thereafter can be modelled using the differential equation
above. Taking vo = 6 find the hovercraft's velocity four seconds later.
111)
With vo = 6 complete the application of one step of the modified Euler method
(given below) with a step-length of h = 4 to approximate the solution to the
differential equation at t = 4s. Compare the approximation you obtain with the exact
value from part ii).
Modified Euler method:
k1 = hf (vo)
k2 = hf(vo + k1)
vi = vo +;(k1 + k2).
Transcribed Image Text:4. The velocity of a body moving through a resisting medium with resistance proportional to the square of the velocity can be modelled by the differential equation dv -0.003 v?, v(0) = vo. dt i) By separating the variables show that the velocity is given by vo v(t): 1+ 0.003 vot ' On a still day a small hovercraft is moving at 6m/s when its fan suddenly fails. The motion of the hovercraft thereafter can be modelled using the differential equation above. Taking vo = 6 find the hovercraft's velocity four seconds later. 111) With vo = 6 complete the application of one step of the modified Euler method (given below) with a step-length of h = 4 to approximate the solution to the differential equation at t = 4s. Compare the approximation you obtain with the exact value from part ii). Modified Euler method: k1 = hf (vo) k2 = hf(vo + k1) vi = vo +;(k1 + k2).
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