1. I'm told that the answer is A, but I can't seem to get it as a solid answer. What am I missing when solving this? I know to ignore the solid in the calculations, as well as that I need to calculate it using Kc and not Kp. 4. The value of Kp for the reaction below is 1.6 at 308 K.NHẠHS(s) = NH3(g) + H2S(g)Initially, 0.50 mol of each of NH4HS, NH3, and H2S is added to a 2.0-L container.WEBHow many moles of NH3 are present at equilibrium?a. 0.10 mol NH3b. 0.20 mol NH3c. 1.3 mol NH3d. 2.6 mol NH3e. 5.1 mol NH3IZED FOR

Kp = Kc (RT)delta n delta n = Change in no of gaseous molecules = (2-0) = 2 R = 0.0821 Latm/molK

Answered: 4. The value of Kp for the reaction…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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I'm told that the answer is A, but I can't seem to get it as a solid answer. What am I missing when solving this? I know to ignore the solid in the calculations, as well as that I need to calculate it using Kc and not Kp.

4. The value of Kp for the reaction below is 1.6 at 308 K.
NHẠHS(s) = NH3(g) + H2S(g)
Initially, 0.50 mol of each of NH4HS, NH3, and H2S is added to a 2.0-L container.
WEB
How many moles of NH3 are present at equilibrium?
a. 0.10 mol NH3
b. 0.20 mol NH3
c. 1.3 mol NH3
d. 2.6 mol NH3
e. 5.1 mol NH3
IZED FOR

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