4. The reaction of metallic cobalt (Co) with oxygen can be described by Co(s) +02COO(s) in which the label (s) indicates reactants and products in a solid form. The Gibbs energy change for this reaction at oxygen pressure po, = latm is given by the expression, kJ + (0.164- k.J AG (T) = -500.8- mol in which T is the temperature in kelvin. This energy change is per mole of O, consumed. You might refer to the Ellingham diagram discussed in class and included in the lecture slides to see if the numbers seem to match the plot for that particular molK reaction. a) Recall that AG = AH - TAS, and that AH and AS only display a weak temperature dependence. Compare to the above equation for AG, What does that tell you about the sign of AS for the reaction? Is it positive or negative? Explain why the sign makes sense for that particular reaction, and also note the slope of this reaction in the Ellingham diagram. Is it consistent? Note that the slopes in the Ellingham diagram relate to the entropy change per mole of O, consumed. b) Recall the equilibrium condition diseussed in class, AG = -RT In K = -RT In Po In which p latm, po, is the oxygen pressure in atm, and R 8.315 kJ mol-'K-1 is the gas constant. If the reaction Co(s)+O2 CoO(s) is in chemical equilibrium at T = 1273K, obtain the equilibrium oxygen pressure po, Compare with what we found using the Ellingham diagram in the lecture slides.

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4. The reaction of metallic cobalt (Co) with oxygen can be described by
Co(s) + O2 CoO(s)
in which the label (s) indicates reactants and products in a solid form. The Gibbs
energy change for this reaction at oxygen pressure po, = latm is given by the
expression,
kJ
AG (T) = -500.8-
kJ
=)T
molK
mol
+ (0.164-
in which T is the temperature in kelvin. This energy change is per mole of O2
consumed. You might refer to the Ellingham diagram discussed in class and included
in the lecture slides to see if the numbers seem to match the plot for that particular
reaction.
a) Recall that AG = AH - TAS, and that AH and AS only display a weak
temperature dependence. Compare to the above equation for AG, What does that
tell you about the sign of AS for the reaction? Is it positive or negative? Explain
why the sign makes sense for that particular reaction, and also note the slope of this
reaction in the Ellingham diagram. Is it consistent? Note that the slopes in the
Ellingham diagram relate to the entropy change per mole of O, consumed.
b) Recall the equilibrium condition discussed in class,
p
AG = -RT In K = -RT In
Po,
In which p= latm, po, is the oxygen pressure in atm, and R=8.315 kJ mol-'K-!
is the gas constant. If the reaction Co(s) +02COO(s) is in chemical equilibrium
at T 1273K, obtain the equilibrium oxygen pressure po,. Compare with what we
found using the Ellingham diagram in the lecture slides.
Transcribed Image Text:4. The reaction of metallic cobalt (Co) with oxygen can be described by Co(s) + O2 CoO(s) in which the label (s) indicates reactants and products in a solid form. The Gibbs energy change for this reaction at oxygen pressure po, = latm is given by the expression, kJ AG (T) = -500.8- kJ =)T molK mol + (0.164- in which T is the temperature in kelvin. This energy change is per mole of O2 consumed. You might refer to the Ellingham diagram discussed in class and included in the lecture slides to see if the numbers seem to match the plot for that particular reaction. a) Recall that AG = AH - TAS, and that AH and AS only display a weak temperature dependence. Compare to the above equation for AG, What does that tell you about the sign of AS for the reaction? Is it positive or negative? Explain why the sign makes sense for that particular reaction, and also note the slope of this reaction in the Ellingham diagram. Is it consistent? Note that the slopes in the Ellingham diagram relate to the entropy change per mole of O, consumed. b) Recall the equilibrium condition discussed in class, p AG = -RT In K = -RT In Po, In which p= latm, po, is the oxygen pressure in atm, and R=8.315 kJ mol-'K-! is the gas constant. If the reaction Co(s) +02COO(s) is in chemical equilibrium at T 1273K, obtain the equilibrium oxygen pressure po,. Compare with what we found using the Ellingham diagram in the lecture slides.
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