4 Only 3. A 0.3246 g sample that might contain NaOH, Na₂CO,, NaHCO, or a permissiblemixture of the bases is titrated with 0.0828 M HCl by the double-indicatormethod. It is found that 30.38 ml of the acid are required to reach thephenolphthalein end point. Methyl orange is then added to the solution and thetitration continued using an additional of 7.83 ml of the acid. Calculate the % ofeach in the sample?4. The protein in a 1.2846-g sample of an oat cereal is determined by the Kjeldahlprocedure for organic nitrogen. The sample is digested with H₂SO4, the resultingsolution made basic with NaOH, and the NH, distilled into 50.00 mL of 0.09552 MHCI. The excess HCI is then back titrated using 37.84 mL of 0.05992 M NaOH.Given that the protein in grains averages 17.54% w/w N, report the % w/wprotein in the sample of cereal.

Problem based on volumetric analysis in which the titration of sample and a solution bis involved.…

4. The protein in a 1.2846-g sample of an oat cereal is determined by the Kjeldahl procedure for organic nitrogen. The sample is digested with H₂SO, the resulting solution made basic with NaOH, and the NH, distilled into 50.00 mL of 0.09552 M HCI. The excess HCI is then back titrated using 37.84 mL of 0.05992 M NaOH. Given that the protein in grains averages 17.54% w/w N, report the % w/w protein in the sample of cereal.

4. The protein in a 1.2846-g sample of an oat cereal is determined by the Kjeldahl procedure for organic nitrogen. The sample is digested with H₂SO, the resulting solution made basic with NaOH, and the NH, distilled into 50.00 mL of 0.09552 M HCI. The excess HCI is then back titrated using 37.84 mL of 0.05992 M NaOH. Given that the protein in grains averages 17.54% w/w N, report the % w/w protein in the sample of cereal.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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O Course Home b Chemistry Question | bartleby G indivuials with austium good to -> A openvellum.ecollege.com/course.html?courseld=16561285&OpenVellumHMAC=446c877376a9bc7ac878d8ad119f4717#10001 Q * E Apps O Maps E Connect - To Do As... O OCCC Moodle P chem work b help Gmail YouTube Balance Chemical E. II Review | Constants | Periodic Table A carbon atom is chiral if it is bonded to four different groups. For example, CHCIBII is chiral, but CCl,BrI is achiral because some of the bonded groups are the same. If a chiral carbon atom is present, then that molecule has a non-superimposable mirror image called an enantiomer. (Figure 1) Part A Identify all the chiral atoms in the below structure by right-clicking* a chiral atom to bring up a menu that includes "Atom Properties." Click on Atom Properties then click the checked box next to the Map field to clear the checkmark. Then enter "1" in the Map *Mac users: Use an equivalent for right- field box to label that chiral carbon atom. clicking.…
Question 27 ОН-, Неat CN CN CN
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