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4. The heat capacity of a substance in Cp 8.41 +2.4346 × 10-5T where T = temperature in K (Kelvin). Develop an equation for Cp so that T can be introduced into the equation in R instead of K. = can be calculated using the equation: gmol-K

4. The heat capacity of a substance in Cp 8.41 +2.4346 × 10-5T where T = temperature in K (Kelvin). Develop an equation for Cp so that T can be introduced into the equation in R instead of K. = can be calculated using the equation: gmol-K

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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J gmol-K 4. The heat capacity of a substance in Cp: 8.41 +2.4346 × 10-5T where T = temperature in K (Kelvin). Develop an equation for Cp so that I can be introduced into the equation in R instead of K. can be calculated using the equation:
Transcribed Image Text:J gmol-K 4. The heat capacity of a substance in Cp: 8.41 +2.4346 × 10-5T where T = temperature in K (Kelvin). Develop an equation for Cp so that I can be introduced into the equation in R instead of K. can be calculated using the equation:
1. Using the table of conversion factors, convert the following and express answers in scientific notation lbm 2,500- ft².hr O O kJ o 1,725 → kg-K 2. Express the following quantities in MLtT and FLtT BTU O lbm m².min lbm R kW m².K ft·lbf lbm-R
Transcribed Image Text:1. Using the table of conversion factors, convert the following and express answers in scientific notation lbm 2,500- ft².hr O O kJ o 1,725 → kg-K 2. Express the following quantities in MLtT and FLtT BTU O lbm m².min lbm R kW m².K ft·lbf lbm-R
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