4. The fractal called the snowflake island (or Koch island) is constructed as follows: Let Io be an equilateral triangle with sides of length 1. The figure I1 is obtained by replacing the middle third of each side of Io with a new outward equilateral triangle with sides of length 1/3 (see figure). The process is repeated, where In+1 is obtained by replacing the middle third of each side of I, with a new outward equilateral triangle 1 The limiting figure as n→o is called the snowflake island. with sides of length 3n+1* (a) Let L, be the perimeter of In. Show that lim L, = ∞ (b) Let A, be the area of Im. Find lim An. (It exists!)

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4. The fractal called the snowflake island (or Koch island) is constructed as follows: Let Io be an equilateral
triangle with sides of length 1. The figure I1 is obtained by replacing the middle third of each side of Io
with a new outward equilateral triangle with sides of length 1/3 (see figure). The process is repeated, where
In+1 is obtained by replacing the middle third of each side of I, with a new outward equilateral triangle
with sides of length
3n+1*
The limiting figure as n→o is called the snowflake island.
(a) Let L, be the perimeter of I,. Show that lim L, = c
(b) Let A, be the area of In. Find lim A,. (It exists!)
Transcribed Image Text:4. The fractal called the snowflake island (or Koch island) is constructed as follows: Let Io be an equilateral triangle with sides of length 1. The figure I1 is obtained by replacing the middle third of each side of Io with a new outward equilateral triangle with sides of length 1/3 (see figure). The process is repeated, where In+1 is obtained by replacing the middle third of each side of I, with a new outward equilateral triangle with sides of length 3n+1* The limiting figure as n→o is called the snowflake island. (a) Let L, be the perimeter of I,. Show that lim L, = c (b) Let A, be the area of In. Find lim A,. (It exists!)
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