please show calc functions ti-84 4.The football coaches at a certain college need their players to bulk up for the following season. In order to accomplishthis, the team administered a company's new milkshake that claimed to increase bodyweight. A random sample of 9players was selected and their weights were recorded before using the milkshake and then again after using themilkshake for 6 months. The results follow:1d (After - Before) 15a. Perform a test of hypothesis using a significance level of .01.22234Player55406178920 10 7b. Construct a 98% confidence interval and interpret it in terms of the problem. Does it support the conclusion ofyour hypothesis test? Explain.

Given information: The data is given, Player d (After - before) 1 15 2 22 3 4 4 0 5 5 6 1 7 20 8 10 9 7 Sample size (n)=9Level of significance (α)=0.01 Find: Test the given claim.Explanation: Define, x: The player of weight before taking new milkshakes. y: The player of weight after taking new milkshakes. This is the paired t-test because the given data have the same subject and the values are dependent on each other. The values affect each other therefore it is a paired t-test. d=y-x=After-Before µd=Average difference in weights. Define the test of hypothesis, H0:µd=0 against H1:µd>0 Perform the above test using a Ti-84 calculator. Below is the path of the perform a pair test. Step 1: Click on STAT then click on Edit to input the given values. Step 2: Click on STAT then Tests then click on 2:T-test. Step 3: Click on Data then Put µ0=0 then select List name L1. Freq. 1 then select an appropriate alternative hypothesis. Then click on calculate. Therefore the given output is, t=3.4864p-value=0.004121x¯=9.3333sd=8.0311 Decision: p-value=0.004121α=0.010.004121<0.01 Reject H0 at a 1% l.o.s. Conclusion: The average body weight of the player increases the after taking new milkshakes. Find CI using Ti-84: Below is the path to find CI using Ti-84. Step 1: Click on STAT then click on Edit to input the given values. Step 2: Click on STAT then Tests then click on 8 T: Interval Step 3: Click on Data then Select List name L1. Freq. 1 then put C-level=0.98 Then click on calculate. Therefore the given output is, 98% CI is, (1.5793, 17.087) Decision: Interval (1.5793, 17.087) in this interval 0 does not lie therefore reject H0 at a 2% l.o.s. Conclusion: The average body weight of the player increases the after taking new milkshakes at a 2% l.o.s. The conclusion of the test and the CI is the same for the different confidence levels.