State hypothesisDefine test, one or 2 sided?Test assumptions (equal variance, normality)State test statistic (t, F, Chi-square)State critical value (1 or 2 sided, degrees of freedom) example: f crit (1, 3, 20)State conclusions.You can use Excel or STATA as an aid to perform the tests, but you should be "in control" of all the steps. Ifapplicable, include STATA outputs, or Excel spreadsheets, in your submission. 4. The following is the distribution of the daily emission of sulfur oxides by anindustrial plant. As can easily be verified, the mean of the distribution is 18.85and its standard deviation is s=5.55. To test the null hypothesis that these dataconstitute a random sample from a normal population, proceed with the followingsteps:Tons of Sulfur Freq.5.0-8.999.0-12.9913.0-16.9917.0-20.9921.0-24.9925.0-28.9929.0-32.99C.310142517a. Find the probabilities that a random variable having the normal distributionwith u-18.85 and 0-5.5 will take on a value less than 8.95, between 8.95 and12.95, between 12.95 and 16.95, between 16.95 and 20.95, between 20.995and 24.95, between 24.95 and 28.95, and greater than 28.95.b. Changing the first and last classes of the distribution to "8.95 or less" and "28.95 or more" find the expectednormal curve frequencies corresponding to the seven classes of the distribution by multiplying theprobabilities obtained in part (a) by the total frequency of 80.Test at the 0.05 level of significance whether the given data may be looked upon as a random sample from anormal distribution. Recall: expected values for any cell cannot be below 5; combine cells if needed.92

To find the probabilities, we can use the standard normal distribution and standardize each value…

Answered: 4. The following is the distribution of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
Rachael got a 660 on the analytical portion of the Graduate Record Exam (GRE). If GRE scores are normally distributed and have mean μ = 600 and standard deviation σ = 30, what is her standardized score?
#31
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.8 parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 6 samples is 4.6 pm with a standard deviation of 1.0 Does the data support the claim at the 0.05 level? Assume the population distribution is approximately normal. Step 4 of 5 : Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places.
1. The strength of steel wire made by an existing process is normally distributed with a mean of 1550 and a standard deviation of 170. A batch of wire is made by a new process, and a random sample consisting of 25 measurements gives an average strength of 1316. Assume that the standard deviation does not change. Is there evidence at the 1% level of significance that the new process gives a larger mean strength than the old? To answer this question, the null hypothesis could be stated as A. μ= 1550 psi B. μ> 1550 psi C.µ + 1550 psi D. μ< 1550 psi
You suspect that people living in urban areas produce on average more garbage (X)than those living in rural areas (Y). To verify this opinion, you draw two samples and collect information on the amount of garbage produced in a month (measured in kilos). The first sample, made of 8 subjects living in an urban area, provides a sample mean equal to 40.5 and a sample standard deviation equal to 5.6; in the second sample, made of 10 subjects living in rural areas, the sample mean is 35.6 and the sample standard deviation is 7.5. It is assumed that the two populations are normal with the same unknown variance.Test the null hypothesis that the two population means are equal against a one-sided alternative according to which people living in urban areas produce on average more garbage than those living in rural areas. Use a 1% significance level.
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.3 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 1030 samples is 5.4 ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.01 level? Step 4 of 5 : Enter the decision rule.
The owner of a local gym has recently surveyed a random sample of n = 300 customers of the club. She would now like to determine whether or not the mean age of her customers is over 35. If so, she plans to alter the fitness equipment to appeal to an older crowd. If not, no changes will be made. Suppose she found that the sample mean was 35.5 years and the population standard deviation, s, was 5 years. What is the p-value associated with the test statistic? O none of these O 0.46 O 0.54 O 0.04
The mean volume of a large population of vials used to be 10.9 ml. To test whether this value has decreased, a random sample of size 300 vials are measured and found to have a sample mean of 10.5 ml. We will assume that the population of vial volumes is normally distributed with standard deviation of 3.6 ml. Test whether the mean population volume has decreased at a level of significance of 1%. Show your relevant steps below. Step 1: Hypotheses: • The null hypothesis Ho is (choose one): µ = 10.9 X = 10.5 x = 10.9 u = 10.5 • For the alternative hypothesis Ha we change the equal sign in Ho to (choose one):
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 14 samples is 4.9 ppm with a variance of 1.2 Does the data support the claim at the 0.01 level? Assume the population distribution is approximately normal. Step 2 of 5 : Find the value of the test statistic. Round your answer to three decimal places.

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