4. The efficiency of a 1 kW DC shunt motor with a supply voltage of 200V is 83% when loaded at its nominal power. The speed of the motor at nominal power is 1500 rpm. (The current through the excitation windings will be neglected.) a-) Find the current drawn by the motor from the power supply. b-) Find the output torque obtained from the shaft of the motor. Formulas: P = V.I.ŋ P = T.w w= 2π. n

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4. The efficiency of a 1 kW DC shunt motor with a supply voltage of 200V is 83% when loaded at its
nominal power. The speed of the motor at nominal power is 1500 rpm. (The current through the
excitation windings will be neglected.)
a-) Find the current drawn by the motor from the power supply.
b-) Find the output torque obtained from the shaft of the motor.
Formulas:
P = V.I.ŋ
P = T.w
w= 2π. n
Transcribed Image Text:4. The efficiency of a 1 kW DC shunt motor with a supply voltage of 200V is 83% when loaded at its nominal power. The speed of the motor at nominal power is 1500 rpm. (The current through the excitation windings will be neglected.) a-) Find the current drawn by the motor from the power supply. b-) Find the output torque obtained from the shaft of the motor. Formulas: P = V.I.ŋ P = T.w w= 2π. n
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