4. The broken back curve shown is to be replaced by a compound curve R2 = 1.8 R1. T1=250m, T2=350m, Δ1/2=30°, Δ2/2=20°, and short tangent =45m. Determine: a. new values of radii b. new values of tangents (ans: a) R1=1101.928m R2=1983.470m, and m=295.261m and n=349.739m)

Given for a compound curve: plus of PI = 14 + 29.31 , Δ = 97 ° 35 ′ 15 ″ ; the first radius R 1 = 400 ′ , Δ 1 = 63 ° 22 ′ 18 ″ , R 2 = 800 ′ . Compute the pluses of PC, PCC, and PT and the length

A simple curve connects two tangents AB and BC with bearings N 36°12' E and N 58°53' E respectively. The PC is a A which is at Sta. 5+234.65 and the B is at Sta. 5+265.09. * Find the radius of the curve. a. 169. 09 m c. 201.12 m b. 137.85 m d. 151.76 m * Using chord basis, compute the degree of the curve. c. 6.78° a. 5.70° b. 7.56° d. 8.31° * Find the external distance. c. 3.36 m a. 2.75 m b. 3.02 m d. 4.01 m * Find the middle ordinate. c. 2.69 m a. 2.96 m b. 3.93 m d. 3.30

The length of the curve of a simple curve having a degree of curve 4o is equal to 210 m. Compute the area of the fillet of the curve. Choices: 1442.69 m2 1244.69 m2 1224.69 m2 1424.69 m2