Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Certainly! Here is how the information from the image would be transcribed for an educational website:
---
**Problem 4:**
Solve the equation:
\[
|x + 3| = \left|\frac{1}{3}x + 8\right|
\]
---
**Explanation:**
This problem involves solving an absolute value equation. The equation is:
\[
|x + 3| = \left|\frac{1}{3}x + 8\right|
\]
To solve this equation, consider the following cases:
1. **Case 1**: \( x + 3 = \frac{1}{3}x + 8 \)
2. **Case 2**: \( x + 3 = -\left(\frac{1}{3}x + 8\right) \)
Solve each case separately to find the values of \( x \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F41a94607-ae05-49d2-a989-bd66a70c4a42%2F2d4a3e89-29f2-462e-bf56-04da65862c64%2F82mbw4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Certainly! Here is how the information from the image would be transcribed for an educational website:
---
**Problem 4:**
Solve the equation:
\[
|x + 3| = \left|\frac{1}{3}x + 8\right|
\]
---
**Explanation:**
This problem involves solving an absolute value equation. The equation is:
\[
|x + 3| = \left|\frac{1}{3}x + 8\right|
\]
To solve this equation, consider the following cases:
1. **Case 1**: \( x + 3 = \frac{1}{3}x + 8 \)
2. **Case 2**: \( x + 3 = -\left(\frac{1}{3}x + 8\right) \)
Solve each case separately to find the values of \( x \).
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