4. Predict the product(s) for each of the following reactions and include stereochemistry when necessary. HI Os04 H,02 1) O3. -78 °C 2) Me,s

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### Predict the Products of the Following Reactions

**Question:**
4. Predict the product(s) for each of the following reactions and include stereochemistry when necessary.

**Given Reactions:**

The reactant molecule is presented as a structural formula consisting of a six-carbon chain with a double bond between the second and third carbon atoms (from the left).

1. **HI (Hydrogen Iodide) Reaction:**
   
   \[
   \text{Reactant} + \text{HI} \rightarrow \text{Product}
   \]

2. **OsO\(_4\), H\(_2\)O\(_2\) (Osmium Tetroxide, Hydrogen Peroxide) Reaction:**

   \[
   \text{Reactant} + \text{OsO}_4, \text{H}_2\text{O}_2 \rightarrow \text{Product}
   \]

3. **O\(_3\) (Ozone) followed by Me\(_2\)S (Dimethyl Sulfide):**
   
   1. \[
   \text{Reactant} + \text{O}_3, -78\,^\circ\text{C} \rightarrow \text{Product}
   \]

   2. \[
   \text{Product} + \text{Me}_2\text{S} \rightarrow \text{Final Product}
   \]

**Explanation:**

1. **Reaction with HI:**
   - HI is expected to react with the double bond in the reactant (alkene) to form an addition product. The hydrogen will add to the less substituted carbon due to Markovnikov's rule, and the iodide will add to the more substituted carbon.

2. **Reaction with OsO\(_4\), H\(_2\)O\(_2\):**
   - OsO\(_4\) reacts with alkenes to form vicinal diols (1,2-diols) via syn addition, meaning both -OH groups will be added to the same side of the double bond.

3. **Ozonolysis (O\(_3\)) followed by reaction with Me\(_2\)S:**
   - Ozone cleaves the double bond to form two carbonyl compounds (either aldehydes or ketones) depending on the substitution pattern of the double bond carbons
Transcribed Image Text:### Predict the Products of the Following Reactions **Question:** 4. Predict the product(s) for each of the following reactions and include stereochemistry when necessary. **Given Reactions:** The reactant molecule is presented as a structural formula consisting of a six-carbon chain with a double bond between the second and third carbon atoms (from the left). 1. **HI (Hydrogen Iodide) Reaction:** \[ \text{Reactant} + \text{HI} \rightarrow \text{Product} \] 2. **OsO\(_4\), H\(_2\)O\(_2\) (Osmium Tetroxide, Hydrogen Peroxide) Reaction:** \[ \text{Reactant} + \text{OsO}_4, \text{H}_2\text{O}_2 \rightarrow \text{Product} \] 3. **O\(_3\) (Ozone) followed by Me\(_2\)S (Dimethyl Sulfide):** 1. \[ \text{Reactant} + \text{O}_3, -78\,^\circ\text{C} \rightarrow \text{Product} \] 2. \[ \text{Product} + \text{Me}_2\text{S} \rightarrow \text{Final Product} \] **Explanation:** 1. **Reaction with HI:** - HI is expected to react with the double bond in the reactant (alkene) to form an addition product. The hydrogen will add to the less substituted carbon due to Markovnikov's rule, and the iodide will add to the more substituted carbon. 2. **Reaction with OsO\(_4\), H\(_2\)O\(_2\):** - OsO\(_4\) reacts with alkenes to form vicinal diols (1,2-diols) via syn addition, meaning both -OH groups will be added to the same side of the double bond. 3. **Ozonolysis (O\(_3\)) followed by reaction with Me\(_2\)S:** - Ozone cleaves the double bond to form two carbonyl compounds (either aldehydes or ketones) depending on the substitution pattern of the double bond carbons
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