4. Our definition of an invertible matrix requires that A be a square n x n matrix. Let's examine what happens when A is not square. For instance, suppose that -1 -2 1 A = -2 -1 B = 1 -2 -1 3 a. Verify that BA = I2. In this case, we say that B is a left inverse of A. b. If A has a left inverse B, we can still use it to find solutions to linear equations. If we know there is a solution to the equation Ax = b, we can multiply both sides of the equation by B to find x = Bb. Suppose you know there is a solution to the equation Ax 3 Use 6 the left inverse B to find x and verify that it is a solution. С. Now consider the matrix 1 -1 C = -2 1 and verify that C is also a left inverse of A. This shows that the matrix A may have more than one left inverse. d. When A is a square matrix, we said that BA this problem, we have a non-square matrix A with BA = happens when we compute AB? I implies that AB = I. In I. What
4. Our definition of an invertible matrix requires that A be a square n x n matrix. Let's examine what happens when A is not square. For instance, suppose that -1 -2 1 A = -2 -1 B = 1 -2 -1 3 a. Verify that BA = I2. In this case, we say that B is a left inverse of A. b. If A has a left inverse B, we can still use it to find solutions to linear equations. If we know there is a solution to the equation Ax = b, we can multiply both sides of the equation by B to find x = Bb. Suppose you know there is a solution to the equation Ax 3 Use 6 the left inverse B to find x and verify that it is a solution. С. Now consider the matrix 1 -1 C = -2 1 and verify that C is also a left inverse of A. This shows that the matrix A may have more than one left inverse. d. When A is a square matrix, we said that BA this problem, we have a non-square matrix A with BA = happens when we compute AB? I implies that AB = I. In I. What
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question

Transcribed Image Text:4. Our definition of an invertible matrix requires that A be a square n x n
matrix. Let's examine what happens when A is not square. For instance,
suppose that
-1
-2
2
1
A
2
-1
B =
=
1
-2
-1
3
a. Verify that BA = I2. In this case, we say that B is a left inverse of A.
b. If A has a left inverse B, we can still use it to find solutions to linear
equations. If we know there is a solution to the equation Ax = b, we
can multiply both sides of the equation by B to find x =
%3D
Bb.
Suppose you know there is a solution to the equation Ax =
-3
Use
the left inverse B to find x and verify that it is a solution.
C.
Now consider the matrix
1
-1
C =
-2
1
and verify that C is also a left inverse of A. This shows that the matrix A
may have more than one left inverse.
d. When A is a square matrix, we said that BA = I implies that AB = I. In
this problem, we have a non-square matrix A with BA = I. What
happens when we compute AB?
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