4. (Normal Distribution) Setup: Define za to be a z-score with an area of a to the right. For example: 20.10 means P(Z > 20.10) 0.10. We would also have, for example: P(Z < -20.10) = 0.10 because of the symmetric property of the normal dis- tribution. = Zo.10 Questions: (a) Find P(-20.13 < Z 20.13). (b) Find P(-%a/2 < Z < 2a/2), where a is any number between 0 and 1. (c) Find the value of za (rounded to 2 decimals) such that P(Z > za) = 0.057. Hint: It may help to draw a picture of what you want to find. X P(Z>Zo.10) 0.10 L

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4. (Normal Distribution)
Setup:
Define za to be a z-score with an area of
a to the right. For example: 20.10 means
P(Z > 20.10) = 0.10. We would also have,
for example: P(Z < -20.10) = 0.10 because
of the symmetric property of the normal dis-
tribution.
Questions:
(a) Find P(-20.13 < Z 20.13).
(b) Find P(-%a/2 < Z <za/2), where a is any number between 0 and 1.
(c) Find the value of za (rounded to 2 decimals) such that P(Z > Z) = 0.057.
Hint: It may help to draw a picture of what you want to find.
Zo.10
1
I
P(Z > Zo.10) 0.10
L
Transcribed Image Text:4. (Normal Distribution) Setup: Define za to be a z-score with an area of a to the right. For example: 20.10 means P(Z > 20.10) = 0.10. We would also have, for example: P(Z < -20.10) = 0.10 because of the symmetric property of the normal dis- tribution. Questions: (a) Find P(-20.13 < Z 20.13). (b) Find P(-%a/2 < Z <za/2), where a is any number between 0 and 1. (c) Find the value of za (rounded to 2 decimals) such that P(Z > Z) = 0.057. Hint: It may help to draw a picture of what you want to find. Zo.10 1 I P(Z > Zo.10) 0.10 L
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