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4. Mr. Doofus McFly decides he is going to put a square peg in a round hole, both initially at 83.00°F. The square peg is made of lead and is 3.500cm on a side and the circular hole is 4.925cm in diameter. With the temperature of the piece with the round hole held constant, the temperature of the square peg is changed until it just barely fits inside the round hole. Calculate the temperature at which that occurs in degrees Celsius. The coefficient of linear expansion for lead is 29.00 x 106°C-!.

4. Mr. Doofus McFly decides he is going to put a square peg in a round hole, both initially at 83.00°F. The square peg is made of lead and is 3.500cm on a side and the circular hole is 4.925cm in diameter. With the temperature of the piece with the round hole held constant, the temperature of the square peg is changed until it just barely fits inside the round hole. Calculate the temperature at which that occurs in degrees Celsius. The coefficient of linear expansion for lead is 29.00 x 106°C-!.

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**Problem Statement:** Mr. Doofus McFly decides he is going to put a square peg in a round hole, both initially at 83.0°F. The square peg is made of lead and is 3.500 cm on a side, and the circular hole is 4.925 cm in diameter. With the temperature of the piece with the round hole held constant, the temperature of the square peg is changed until it just barely fits inside the round hole. Calculate the temperature at which that occurs in degrees Celsius. The coefficient of linear expansion for lead is \(29.00 \times 10^{-6} \, ^\circ\text{C}^{-1}\). **Explanation:** - **Initial Conditions:** - Temperature = 83.0°F - Square Peg: - Material: Lead - Side Length = 3.500 cm - Round Hole: - Diameter = 4.925 cm - **Objective:** - Calculate the temperature change required for the square peg to fit into the round hole by accounting for thermal expansion. - **Coefficient of Linear Expansion:** - Lead: \(29.00 \times 10^{-6} \, ^\circ\text{C}^{-1}\) This problem involves understanding the concept of thermal expansion and applying it to a practical scenario where the dimensions of objects change with temperature.
Transcribed Image Text:**Problem Statement:** Mr. Doofus McFly decides he is going to put a square peg in a round hole, both initially at 83.0°F. The square peg is made of lead and is 3.500 cm on a side, and the circular hole is 4.925 cm in diameter. With the temperature of the piece with the round hole held constant, the temperature of the square peg is changed until it just barely fits inside the round hole. Calculate the temperature at which that occurs in degrees Celsius. The coefficient of linear expansion for lead is \(29.00 \times 10^{-6} \, ^\circ\text{C}^{-1}\). **Explanation:** - **Initial Conditions:** - Temperature = 83.0°F - Square Peg: - Material: Lead - Side Length = 3.500 cm - Round Hole: - Diameter = 4.925 cm - **Objective:** - Calculate the temperature change required for the square peg to fit into the round hole by accounting for thermal expansion. - **Coefficient of Linear Expansion:** - Lead: \(29.00 \times 10^{-6} \, ^\circ\text{C}^{-1}\) This problem involves understanding the concept of thermal expansion and applying it to a practical scenario where the dimensions of objects change with temperature.
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