4. Moving at 30.0 m/s, a car of mass 6.00 x 102 kg collides with a stationary truck of mass 2.00 x 103 kg. If the two vehicles interlock as a result of the collision, what is the velocity of the car-truck system? (1) 2.00 m/s (2) 7.00 m/s (3) 9.00 m/s (4)12.0 m/s A 0.25 kg pool ball with a velocity of 15.0 m/s strikes another 0.25 kg pool ball at rest. If the velocity of the first ball drops to 6.0 m/s, what would the velocity of the second ball become if there was no change in direction? (1) 6.0 m/s (2) 8.0 m/s 5. (3) 7.0 m/s (4) 9.0 m/s
4. Moving at 30.0 m/s, a car of mass 6.00 x 102 kg collides with a stationary truck of mass 2.00 x 103 kg. If the two vehicles interlock as a result of the collision, what is the velocity of the car-truck system? (1) 2.00 m/s (2) 7.00 m/s (3) 9.00 m/s (4)12.0 m/s A 0.25 kg pool ball with a velocity of 15.0 m/s strikes another 0.25 kg pool ball at rest. If the velocity of the first ball drops to 6.0 m/s, what would the velocity of the second ball become if there was no change in direction? (1) 6.0 m/s (2) 8.0 m/s 5. (3) 7.0 m/s (4) 9.0 m/s
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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This is multiple choice is just give me the number it is. These are not 2 questions but 2 parts. So can you answer both. Thank you!! They are questions 4 and 5
![ans
32.
If a net force of 10. newtons acts on a 6.0 kg mass for 8.0 seconds, the total change of
momentum of the mass is
(1) 48. kgm/s
(2) 60. kgm/s
(3) 80. kgm/s
(4) 480. kgm/s
| 3.
What is the change in velocity of the mass in question #2?
13.3 m/s
(2) 80.0 m/s
(3) 20.0 m/s
(4) 480. m/s
4. Moving at 30.0 m/s, a car of mass 6.00 x 10² kg collides with a stationary truck of mass
2.00 x 10 kg. If the two vehicles interlock as a result of the collision, what is the
velocity of the car-truck system?
(1) 2.00 m/s
(2) 7.00 m/s
(3) 9.00 m/s
(4)12.0 m/s
A 0.25 kg pool ball with a velocity of 15.0 m/s strikes another 0.25 kg pool ball at rest.
If the velocity of the first ball drops to 6.0 m/s, what would the velocity of the second
ball become if there was no change in direction?
(1) 6.0 m/s
(2) 8.0 m/s
5.
(3) 7.0 m/s
(4) 9.0 m/s
3,6. Force applied to an object multiplied by the time applied is defined as
(1) momentum
(2) velocity
(3)impulse
(4) mass
A 50.0 kg projectile leaves a 1.00 x 103 kg launcher with a velocity of 8.00 x 10² m/s.
What is the magnitude of the recoil velocity of the launcher?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39b50207-a522-4a91-9dcf-d2afb645e058%2F5223c003-762b-4cdc-aa8a-102cee5f7093%2Fp5rodo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ans
32.
If a net force of 10. newtons acts on a 6.0 kg mass for 8.0 seconds, the total change of
momentum of the mass is
(1) 48. kgm/s
(2) 60. kgm/s
(3) 80. kgm/s
(4) 480. kgm/s
| 3.
What is the change in velocity of the mass in question #2?
13.3 m/s
(2) 80.0 m/s
(3) 20.0 m/s
(4) 480. m/s
4. Moving at 30.0 m/s, a car of mass 6.00 x 10² kg collides with a stationary truck of mass
2.00 x 10 kg. If the two vehicles interlock as a result of the collision, what is the
velocity of the car-truck system?
(1) 2.00 m/s
(2) 7.00 m/s
(3) 9.00 m/s
(4)12.0 m/s
A 0.25 kg pool ball with a velocity of 15.0 m/s strikes another 0.25 kg pool ball at rest.
If the velocity of the first ball drops to 6.0 m/s, what would the velocity of the second
ball become if there was no change in direction?
(1) 6.0 m/s
(2) 8.0 m/s
5.
(3) 7.0 m/s
(4) 9.0 m/s
3,6. Force applied to an object multiplied by the time applied is defined as
(1) momentum
(2) velocity
(3)impulse
(4) mass
A 50.0 kg projectile leaves a 1.00 x 103 kg launcher with a velocity of 8.00 x 10² m/s.
What is the magnitude of the recoil velocity of the launcher?
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