4. In dogs, the tendency to bark while traliling is due to a dominant gene while silent trailing is recessive. Erect ears is dominant over drooping ears. Show the offspring expected from a cross between two erect-eared barkers who are heterozygous for both genes a. Possible genotypes for Barking while trailing: b. Possible genotypes for Erect ears: Silent: Drooping ears c. Male genotype: d. Female Male possible gametes genotype:Female possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio:

4. In dogs, the tendency to bark while traliling is due to a dominant gene while silent trailing is recessive. Erect ears is dominant over drooping ears. Show the offspring expected from a cross between two erect-eared barkers who are heterozygous for both genes a. Possible genotypes for Barking while trailing: b. Possible genotypes for Erect ears: Silent: Drooping ears c. Male genotype: d. Female Male possible gametes genotype:Female possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio:

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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4. In cocker spaniels, the following genotypes and phenotypes are found:AABB = white A-bb = red aabb = lemon AaB- = black aaB- = liver AABb = greyb. What proportion of these offspring would be expected to be black?
3. One parent is homozygous for the allele for myostatin that results in big muscles and the other parent is heterozygous (MM x Mm). a. Part A (fill in the boxes): M м M m b. Part B (fill in the boxes): Total number of offspring with the heavily muscled phenotype Proportion and percent of heavily muscled offspring Total number of offspring with the in-between phenotype Proportion and percent of in-between offspring Total number of offspring with typical muscles Proportion and percent of typical muscled offspring Total: 100%
3. Codominance is when two dominant alleles of contrastingpair fully expressed at the same time in heterozygousindividual. Which of the following situation is an example ofcodominance?A. Jo mated the red bull with the white cow to produce a roan cow.B. Melissa traces her blood type by crossing the blood type of herparents.C. James passed a genetic disorder hypertrichosis pinnae aurisor hairy ear to his son.D. Tess crosses the red carnation flower plant with white flowercarnation plant to produce a pink flower plant.
8. Albinism in humans is heritable condition resulting in the inability to produce the pigment melanin, which is responsible for hair, eye and skin coloration. The allele for the albino condition is recessive to the allele for melanin production. What is the probability of two heterozygous parents producing a family of two normal children and one albino child?
3. Albinism is a recessive trait. Determine the genotypes of the parents and offspring. a. A normal father and an albino mother have eight children, four normal (2 male & 2 female) and four albino ((2 male & 2 female) b. A normal father and an albino mother have eight children which are all normal (4 male & 4 female) c. Construct a pedigree of the families in (a) and (b). Assume that one of the normal children in (b) and one of the albino children in (a) become the parents of eight children (4 male & 4 female). Extend the pedigree to include them, predicting their phenotypes (normal or albino). ● Use "A" for the allele associated with the dominant phenotype, and lowercase "a" for the allele associated with the recessive phenotype.
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11. A polygenic trait is also called multiple a. continuous trait holandric gene d. X-link gene b. A plant bearing pink flowers is allowed to pollinate itself. Every generation thereafter, the plant still produces pink flowers. This condition is known as hybridization 12. C. pure breeding a. b. incomplete dominance d. segregation 13. A homozygous red-flowered plant was crossed with a homozygous white-flowered plant and resulted in an offspring with red flowers. This demonstrates a case of dihybrid cross monohybrid cross a. C. b. dominance d. pure breeding How many chromosomes does a human gamete have? 14. 12 a. C. 24 b. 23 d. 46 If a heterozygous tall plant (TI) is crossed with a short plant (t), how many percent of the offspring are heterozygous tall? 15. a. 25% с. 75% b. 50% d. 100% Critical Thinking Are you in favor of the idea that couples should undergo genetic counseling? Why? Explain why Gregor Mendel chose pea plants for his experiments. Albinism is caused by a mutation;…
1. Honeybee workers undergo a resistant behavioral pattern called hygienic behavior. Susceptible worker genotypes failed to remove the diseased larvae, so that the disease spread easily throughout the honeybee colony. a) When inbred lines of resistant genotypes were crossed with inbred lines of susceptible genotypes, the F1 worker bees showed unhygienic behavior.Is hygienic behavior dominant or recessive in these bees? Why?
1. Two loci found in mice are suspected to be linked. To test this hypothesis, a group of graduate students performed a test cross between mice that are true breeding for both dominant traits and mice that are true breeding for both recessive traits. Individuals from the F1 generation were crossed with individuals that express both recessive traits. The phenotypic results are shown in the table below. Use chi-square analysis to determine if the graduate students’ hypothesis is supported by the evidence. Phenotype Number of OffspringDominant 1, Recessive 2 132Dominant 1, Dominant 2 128Recessive 1, Recessive 2 118Recessive 1, Dominant 2 124 a. What are the degrees of freedom and the critical chi-square value (from the table)?b. What is the calculated chi-square value?c. Do the results support that the loci are linked or that they are independently assorted (unlinked)?
13. In another species of berry, Rass berrylis, the allele for yellow fruit (F) is dominant to the allele for red fruit (f), and the allele for thorny stems (T) is dominant to the allele for thornless stems (t). The gene for fruit colour is 17.4 map units from the stem thorniness. gene for a. Draw a Punnett square to illustrate the cross between a Rass b. with red berries and thornless stems and a plant that was heterozygous for both characteristics. (The parents of the heterozygous plant were yellow-fruiting and thorny, and red- fruiting and thornless, and were homozygous for both traits.)
1. In mice, black fur (B) is dominant over brown fur (b). Breeding a brown mouse and a homozygous black mouse produces all black offspring. a. What is the genotype of the gametes produced by the brown-furred parent? b. What genotype is the brown-furred parent? . c. What genotype is the black-furred parent? . d. What genotype is the black-furred offspring?. e. If two F, mice are bred with one another, what phenotype will the F, offspring be, and in what proportion? phenotype. proportion.
23. In horses, black color is influenced by the dominant allele B and chestnut coat color is influenced by the recessive allele b. Trotting gait is due to a dominant allele T, pacing gait to the recessive allele t. A black trotter who is homozygous for both traits is crossed to a chestnut pacer. a. What are the genotypes of the Pgeneration? b. What will be the genotype and phenotype of the F1 generation? c. Draw a punnett square showing the cross of two F1 generation horses. What is the phenotypic ratio of all the combinations?